If you roll a standard die and flip a penny at the same time, there are 12 possible outcomes. You can find this out quickly by multiplying the number of outcomes of the coin (2) by the number of outcomes of the die (6).
Here they are:
Heads, 1
Heads, 2
Heads, 3
Heads, 4
Heads, 5
Heads, 6
Tails, 1
Tails, 2
Tails, 3
Tails, 4
Tails, 5
Tails, 6
7
Four outcomes, three combinations.
If you flip a coin 2 times, there are 4 possible outcomes; HH, HT, TH, TT.
Two possible outcomes for each flip. 2,048 possible histories of 11 flips.
There are 24 = 16 ordered outcomes, that is outcomes in which the order of the results is relevant. If not, there are 5 outcomes (0 heads, 1 head, 2 heads, 3 heads and 4 heads).
7
If you disregard the sequence of outcomes, there are 6 possible outcomes: 0H 5T 1H 4T 2H 3T 3H 2T 4H 1T and 5H 0T If not, there are 25 = 32 outcomes: TTTTT, TTTTH, TTTHT etc.
Four outcomes, three combinations.
2. There is heads and there is tails.
If you flip a coin 2 times, there are 4 possible outcomes; HH, HT, TH, TT.
2*2*6 = 24 outcomes.
-- 8 possibilities if the coins are different colors. -- Only 4 possibilities if you can't tell the coins apart.
There are sixteen different outcomes. To figure this you multiply the number of possible outcomes for each coin, which is 2 for all of them. So you take 2^4 which comes out to 16.
I am guessing SamJoe, means SAM and JOE not one person, so three people flip a coin, we have two outcomes each times, so 23= 8 possible outcomes. If you had n people, there would be 2n outcomes. For example, if two people flip there are 4 outcomes HH TT HT or TH
When flipping a coin 8 times, each flip has 2 possible outcomes: heads or tails. Therefore, the total number of possible outcomes is calculated by raising the number of outcomes for one flip to the power of the number of flips: (2^8). This equals 256 possible outcomes.
Two possible outcomes for each flip. 2,048 possible histories of 11 flips.
2...face up and face down.