1,2,3,4 1+2+3+4=10 4 times 3 times 2 times 1 =24 24 counting numbers
10
9
There are a total of 189 digits in the numbers 1 to 99. To calculate this, we can consider the numbers from 1 to 9, which have a total of 9 digits. Then, we add the numbers from 10 to 99, which have 2 digits each, for a total of 2 * 90 = 180 digits. Adding these together gives us 9 + 180 = 189 digits in total.
128
Not couting 1 and 1000, there would be 998 numbers.
Infinitely many. The number pi , for example, is between 1 and 1000 and, since pi is a transcendental number, it contains infinitely many digits. Plus, there are all the irrational numbers - each with infinitely many digits, and all the rationals with recurring decimals - again with infinitely many digits.
10001
There are 2892 digits.
I suggest you calculate (1) how many numbers are in total, and (2) how many numbers in that range do NOT have 6 as a digit. Then you can subtract the result of (1) minus the result of (2).
2893 digits in all, made up as follows: 9 1-digit numbers (1 to 9) = 1*9 = 9 digits 90 2-digit numbers (10 to 99) = 2*90 = 180 digits 900 3-digit numbers (100 to 999) = 3*900 = 270 digit 1 4-digit number (1000) = 4*1 = 4 digits
11000
Using only arrangements of the given digits: without repeating digits, 15. with repetition, 39. The answer does not include numbers such as 2^3 = 8 or 3^(2+1) = 27
solution: we know that there are 25 prime numbers are between 1-100 and 168 prime numbers less than 1000. 100 x 100=10000(5 digits) 999 x 999=998001(6 digits) 1000 x 1000=1000000(7 digits) so our answer should be same as the number of prime numbers between 100 to 999. hence, 168-25=143. 143 prime numbers will be there less than 1000 whose square has 5 or 6 digits.
There are 116 1s in the first 1000 digits of pi.
Four digit numbers span from 1000 to 9999. This totals (9999-1000) +1 = 9000 different four digit numbers
9000 of them. All of the numbers 1 thru 9999 EXCEPT 1 thru 999. 9999 - 999 = 9000.