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STOP - This seems to be a homework assignment.
I strongly suggest you try to do it first, so that you gain the value of the lesson.
The prime factors of 4725 are 3, 3, 3, 5, 5, and 7.
Combining these in all of their combinations, along with 1 which is always a divisor, the divisors of 4725 are ...
- 1 (1)
- 3 (3)
- 5 (5)
- 7 (7)
- 9 (3 3)
- 15 (3 5)
- 21 (3 7)
- 25 (5 5)
- 27 (3 3 3)
- 35 (5 7)
- 45 (3 3 5)
- 63 (3 3 7)
- 75 (3 5 5)
- 105 (3 5 7)
- 135 (3 3 3 5)
- 175 (5 5 7)
- 189 (3 3 3 7)
- 225 (3 3 5 5)
- 315 (3 3 5 7)
- 525 (3 5 5 7)
- 675 (3 3 3 5 5)
- 945 (3 3 3 5 7)
- 1575 (3 3 5 5 7)
- 4725 (3 3 3 5 5 7)
... so, there are 24.
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