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The answer is ‎300.

(9,19,29,39,49,59,69,79,89,90,91,92,93,94,95,96,97,98,99) = 20

20*10 (ten hundreds) = 200

Add another 100 for the nine hundred (from 900 to 999)

200+100 = 300

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To determine how many times the digit 9 is written when writing numbers from 1 to 10000, we can consider the pattern of its occurrence in each place value. In the units place, the digit 9 appears 1000 times (from 9 to 9999). In the tens place, the digit 9 appears 1000 times (from 90 to 99, 190 to 199, and so on). In the hundreds place, the digit 9 appears 1000 times (from 900 to 999, 1900 to 1999, and so on). Therefore, the digit 9 is written 3000 times in total when writing numbers from 1 to 10000.


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To find how many times the digit '7' appears in the numbers from 1 to 1000, you can analyze each digit place (hundreds, tens, and units). In each of these places, '7' appears 100 times (from 0-999) as each digit can take on values from 0 to 9. Thus, there are 300 occurrences of '7' in total from 1 to 999. Additionally, the number 1000 does not contain a '7', so the total remains 300.


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