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The digit 9 appears in the units place 100 times from 1 to 1000 (9, 19, 29,..., 989, 999). It also appears in the tens place 100 times (90, 91, 92,..., 99, 190, 191,..., 199, 290,..., 999). Therefore, the digit 9 appears a total of 200 times from 1 to 1000.

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The answer is ‎300.

(9,19,29,39,49,59,69,79,89,90,91,92,93,94,95,96,97,98,99) = 20

20*10 (ten hundreds) = 200

Add another 100 for the nine hundred (from 900 to 999)

200+100 = 300

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Wiki User

12y ago
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269

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Anonymous

4y ago
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17

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Anonymous

4y ago
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Q: How many times does the digit 9 appears from 1 to 1000?
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