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There are 10 different sets of teachers which can be combined with 4 different sets of students, so 40 possible committees.

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How many ways can a committee of 6 be chosen from 5 teachers and 4 students if all are equally eligible?

To calculate the number of ways a committee of 6 can be chosen from 5 teachers and 4 students, we use the combination formula. The total number of ways is given by 9 choose 6 (9C6), which is calculated as 9! / (6! * 3!) = 84. Therefore, there are 84 ways to form a committee of 6 from 5 teachers and 4 students if all are equally eligible.


How many different committees can be formed from 10 teachers and 30 students if the committee consists of 2 teachers and 2 students?

There are (10 x 9)/2 = 45 different possible pairs of 2 teachers. For each of these . . .There are (30 x 29)/2 = 435 different possible pairs of students.The total number of different committees that can be formed is (45 x 435) = 19,575 .


A committee consisting of 6 people is to be selected from eight parents and four teachers Find the probability of selecting three parents and three teachers?

8/33


What is a KWL chart or graph?

KWL charts are a great tool for students and teachers. It can be used with any subject to help students with comprehension. In the first column students write what they know about the subject. The second column (W) students write what they want to know about a subject. The third column (L) is where students write what they learned. KWL charts are a great way to help students learn not just what they already know but help them to see what they are learning.


What percentage of the world are teachers?

in my opinion, 5% of the world are teachers bcoz 5 is my lucky number and it helps me all the time. Abid Shah

Related Questions

How many different committees can be formed from 6 teachers and 33 students if the committee consists of 3 teachers and 2 students?

There are 10560 possible committees.


How many ways can a committee of 6 be chosen from 5 teachers and 4 students if all are equally eligible?

To calculate the number of ways a committee of 6 can be chosen from 5 teachers and 4 students, we use the combination formula. The total number of ways is given by 9 choose 6 (9C6), which is calculated as 9! / (6! * 3!) = 84. Therefore, there are 84 ways to form a committee of 6 from 5 teachers and 4 students if all are equally eligible.


How many ways can a committee of 2 teachers and 5 students to be formed from 7 teachers and 25 students?

For this type of problem, order doesn't matter in which you select the number of people out of the certain group. We use combination to solve the problem.Some notes to know what is going on with this problem:• You want to form a committee of 2 teachers and 5 students to be formed from 7 teachers and 25 students • Then, you select 2 teachers out of 7 without repetition and without considering about the orders of the teachers.• Similarly, you select 5 students out out 25 without repetition and without considering about the orders of the students.Therefore, the solution is (25 choose 5)(7 choose 2) ways, which is equivalent to 1115730 ways to form such committee!


How many different committees can be formed from 11 teachers and 48 students?

To determine the number of different committees that can be formed from 11 teachers and 48 students, we need to clarify the size of the committee and whether there are any restrictions on the selection. If we assume that any combination of teachers and students can be chosen without restrictions, the total number of possible combinations is (2^{11} \cdot 2^{48} = 2^{59}). This accounts for every possible subset of teachers and students, including the empty committee.


A school committee consists of 2 teachers and 4 students. The number of different committees that can be formed from 5 teachers and 10 students is?

To form a committee of 2 teachers from 5, we use the combination formula ( \binom{n}{r} ), where ( n ) is the total number and ( r ) is the number chosen. The number of ways to choose 2 teachers from 5 is ( \binom{5}{2} = 10 ). For the 4 students from 10, the number of ways is ( \binom{10}{4} = 210 ). Therefore, the total number of different committees is ( 10 \times 210 = 2100 ).


Does teachers tickle students?

no teachers don't tickle students


What is the noun in three students and their teachers are coming?

The nouns in the sentence are students and teachers.


Why should teachers challenge students?

why should teachers challenge students


How many different committees can be formed from 9 teachers and 49 students if the committee consists of 2 teachers and 4 students?

Possibilities are (9 x 8)/2 times (49 x 48 x 47 x 46)/24 = 366,121,728/48 =7,627,536 different committees.


The average age of a group of teachers and students is 20 The average age of the teachers is 35 The average age of the students is 15 What is the ratio of teachers to students?

1 : 3


What is a sentence using the word committee?

I am on the housing committee. I am on the committee of teachers who regulate the rules for school. The city council has a committee meeting once a month.


How many different committees can be formed from 10 teachers and 30 students if the committee consists of 2 teachers and 2 students?

There are (10 x 9)/2 = 45 different possible pairs of 2 teachers. For each of these . . .There are (30 x 29)/2 = 435 different possible pairs of students.The total number of different committees that can be formed is (45 x 435) = 19,575 .