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The first position can be filled by eight, the second by seven, and so on. So the number of possibilities are:

8!/3! = 8*7*6*5*4 = 6720

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Q: How many ways can the 5 starting positions on s basketball team be filled with 8 men who can play any of the position?
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Continue Learning about Statistics

All seven-digit telephone numbers in a town begin with 245 how many telephone numbers may be assigned in the town if the last 4 digits do not begin or end in a zero?

There are seven positions: _ _ _ _ _ _ _ Each must be filled by number 0-9 and numbers can be repeated. The first three positions must be 2,4,5, therefore, 2 4 5 _ _ _ _ For the other for positions, the 4th and 7th position cannot be 0 (therefore only 9 possibilities: 1-9) and the 5th and 6th position can be any number (10 possibilities: 0-9). Therefore, the total number of possibilities is 9 * 10 * 10 * 9 = 8100 since the positions are independent.


How many different three-letter initials can people have?

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What is the probability of picking a consonant out of a bag filled with each letter of the alphabet?

The probability is 21/26.


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How many numbers greater than 4000 can be formed with the digits 2 3 4 5 and 6 if no digit is used more than once in a number?

The numbers between 4,000 and 10,000 _ _ _ _ 1st place only can filled by 4, 5, and 6 2nd place only can filled by the other 4 digit 3rd place only can filled by the other 3 digit 4th place only can filled by the other 2 digit So: 3 x 4 x 3 x 2 = 72 numbers The numbers greater than 10,000 5 x 4 x 3 x 2 x 1 = 120 numbers The total is 72 + 120 = 192 numbers can formed.

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