there should be 720 ways !
5!/(2!*2!) = 30 ways.
This is how you do it, there are 7 letters in average so it would be, 7x6x5x4x3x2x1.
(5 x 4 x 3 x 2 x 1) = ( 5 ! ) = 120 ways.
There are (4*3)*(6*5*4*3*2*1) = 8640 ways.
Make notes that:There are 2 c's in the given word.There are 2 o's in the given word.Since repetition is restricted when rearranging the letters, we need to divide the total number of ways of rearranging the letters by 2!2!. Since there are 9 letters in the word to rearrange, we have 9!. Therefore, there are 9!/(2!2!) ways to rearrange the letters of the word 'chocolate'.
We can rearrange the letters in tattoo 60 times.
there should be 720 ways !
4! = 24 ways.
5!/(2!*2!) = 30 ways.
You can arrange the letters in group One hundred and twenty-five different ways.
24 ways
The nine letters in chocolate can be rearranged in 362,880 different ways.
You can rearrange them 120 ways. Five of those ways could be considered English words: satin, stain, saint, antis, Tinas
To calculate the number of ways the letters in the word "pencil" can be rearranged, we first determine the total number of letters, which is 6. Since there are two repeated letters (the letter 'e'), we divide the total number of letters by the factorial of the number of times each repeated letter appears. This gives us 6! / 2! = 360 ways to rearrange the letters in the word "pencil."
This is how you do it, there are 7 letters in average so it would be, 7x6x5x4x3x2x1.
"Colonialist" has 11 letters, including 3 pairs of matching letters, so the letters can be arranged in: 11! / (2! * 2! * 2!) = 4,989,600 ways.