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If a fair six sided die was rolled 4 times what is the probability of getting at least one ace one?
Wiki User
∙ 15y ago
p(one) = 1/6
p(not one) = 5/6
p(at least one) = 1 - p(failure)
p(failure) = (4C0)(5/6)^4 = 1 x 625/1,296 = 0.48
p(at least one) = 1 - 0.48 = 0.52
Wiki User
∙ 15y ago
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