26/52 cards are black and 13/52 cards are diamonds so the total probability of either a diamond or a black card is 39/52 or 3/4
p = 0.75
# of diamond card = 13 # of black 7 card = 2 P(diamond and black 7) = 13/52 * 2/51 = 1/4 * 2/51 Answer = 1/102
There are 13 diamonds in a 52-card deck so the probability to get a diamond is 13/52=1/4=0.25
It is 3/13. The fact that the card is black makes no difference since the probability is the same for both colours.
The probability is one in fifty-two.
The probability of drawing a diamond is a standard deck of 52 cards is 13 in 52, or 1 in 4, or 0.25.
# of diamond card = 13 # of black 7 card = 2 P(diamond and black 7) = 13/52 * 2/51 = 1/4 * 2/51 Answer = 1/102
In a normal deck of cards, it is 1.
The probability is 1/2.
"Neither card is red" is the same as "both cards are black". The probability that the first card is black is 26 out of 52, or 1/2. Given that the first card is black, there are 51 cards remaining, of which 25 are black; thus the conditional probability that the second card is also black is 25/51. The probability that both cards are black is the product of these two probabilities: 1/2 * 25/51 = 25/102, or about 24.51%.
There are 13 diamonds in a 52-card deck so the probability to get a diamond is 13/52=1/4=0.25
It is 3/13. The fact that the card is black makes no difference since the probability is the same for both colours.
The probability is one in fifty-two.
The probability of drawing a diamond is a standard deck of 52 cards is 13 in 52, or 1 in 4, or 0.25.
It is 13/52 = 1/4.
There are 6 black face card in a deck of 52 cards, so the probability of getting a black face card is 6/52 = 3/26
0.5
There are 4 suits in a deck of cards; each suit has a probability of being selected of 1/4. So, probability of a diamond is 1/4 or 0.25.