The answer is 1/3. There are six possible outcomes (1 to 6) of which two (3 or 4) are favourable so the probability is 2/6 or 1/3. In general, if A and B are two events, then Pr (A or B) = Pr(A) + Pr(B0 - Pr(A and B) [the last bit is because you are double counting those events] Here Pr(A) = Pr(3) = 1/6, Pr(B) = Pr(4) = 1/6 and Pr(A and B) = Pr(3 and 4 - simultaneously) = 0 So Pr(3 or 4) = 1/6 + 1/6 + 0 = 1/3
Assuming you are talking about fair, six-sided dice, then the probability of rolling a 1 on the first roll in 1/6, and the probability of rolling a 2 on the second roll is 1/6. Putting these together, the probability of rolling 1 on the first die and 2 on the second die is 1/36. If you do not care about the order, then you could roll 1,2 or 2,1; in this case the probability would be 2/36, or 1/18.
There is one three on a dice, and there are six sides, so the probability of rolling a three is 1 out of 6 or about 16.6%.
It is 0.5
The probability of getting an odd number when you roll one die is 1 in 2. In order to get an odd sum with two dice, one of them has to be odd and one of them has to be even. The probability of rolling an odd sum is still 1 in 2, since each die is unrelated in probability to the other.
The probability of rolling a seven with one roll of a standard number cube is zero.
If zero is the number on one of the 9 sides, then the probability is 8/9 = 88.9% (rounded)If zero is not the number on any one of the 9 sides, then the probability is 100%.
The probability of getting a 7 on one roll of a die is zero.If you meant to ask about two dice, the probability is 6 in 36, or 1 in 6.
Since there are 6 sides to the die, the probability of rolling a 5 on one roll is 1/6. Since each roll is an independent event the probability of the multiple results is the product of the probability of each result. So 2 consecutive 5's would occur with a probability of (1/6)(1/6) = 1/36
One sixth
one out of 6
Assuming you are talking about fair, six-sided dice, then the probability of rolling a 1 on the first roll in 1/6, and the probability of rolling a 2 on the second roll is 1/6. Putting these together, the probability of rolling 1 on the first die and 2 on the second die is 1/36. If you do not care about the order, then you could roll 1,2 or 2,1; in this case the probability would be 2/36, or 1/18.
Since there are 6 sides to the die, the probability of rolling a 5 on one roll is 1/6. Since each roll is an independent event the probability of the multiple results is the product of the probability of each result. So 2 consecutive 5's would occur with a probability of (1/6)(1/6) = 1/36
There is one three on a dice, and there are six sides, so the probability of rolling a three is 1 out of 6 or about 16.6%.
1:6. It's easy to see why if you think about it a certain way... First, roll one die. Whatever number you roll, there is exactly one number you can roll on the other die to total seven. The odds that you'll roll that one other number is 1:6 (because the die has 6 sides).
It is 1/6.
One in 6.
On a standard 6 sided die then the probability would be 1/6 if it is a 12 sided die then it would be 1/12 it varies by how man sides of the die there are.