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Imagine the 5 seats on the stage being filled in some order. The first seat can be occupied by any one of the 5 speakers. With each choice of 5 speakers, there are four who can go for the next seat. Then, wiyth each of the 5*4 choices, there are 3 speakers left to go for the next.
Continuing in this way, the answer is 5*4*3*2*1 = 5! = 120 ways.
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How many different ways can 8 computer operators be seated in row?
The number of different ways that 8 computer operators can be seated in a row is the same as the number of permutations of 8 things taken 8 at a time. That is 8 factorial, which is 40,320. Think of it this way... You have 8 choices for the first seat, 7 choices for the second seat, 6 choices for the third seat, and so on to 1 choice for the last seat. That is 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1, otherwise known as 8 factorial.
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