Not necessarily.
The calculation is equal to the sum of their probabilities less the probability of both events occuring. If two events are mutually exclusive then the combined probability that one or the other will occur is simply the sum of their respective probabilities, because the chance of both occurring is by definition zero.
It depends on the events. The answer is 0.5*(Total number of events - number of events with probability = 0.5) That is, discount all events such that their probability (and that of their complement) is exactly a half. Then half the remaining events will have probabilities that are greater than their complement's.
I am assuming that this die is fair die and the coin is not biased. The probability of getting a number less than 3 is the probability of rolling a 1 or a 2 i.e. 1/6 + 1/6 = 2/6 which simplifies to 1/3. The probability of getting a head when you flip a fair coin is 1/2. Both are independent events, so the probability of getting a number less than 3 and getting a head is 1/3 x 1/2 = 1/6. One can get the same answer from a sample space diagram
Probability can not be less than 0 or greater than 1. A probability of 0 means there is no possibility whatsoever of an event occurring. A probability of 1 means that the event is guaranteed to occur no matter what.
No; because probability can never be less than zero.
They are "events that have the same probability". Nothing more, nothing less.
The calculation is equal to the sum of their probabilities less the probability of both events occuring. If two events are mutually exclusive then the combined probability that one or the other will occur is simply the sum of their respective probabilities, because the chance of both occurring is by definition zero.
It depends on the events. The answer is 0.5*(Total number of events - number of events with probability = 0.5) That is, discount all events such that their probability (and that of their complement) is exactly a half. Then half the remaining events will have probabilities that are greater than their complement's.
Since the probability of both events is not mutally exlcusive (you could draw both at the same time), the probability is: P(queen)+P(face)-P(both) (4/52)+(12/52)-(4/52) 12/52, which is a bit less than 0.25
There are many such events. The probability of throwing a 1 or 2 on one roll of a die, for example.
I am assuming that this die is fair die and the coin is not biased. The probability of getting a number less than 3 is the probability of rolling a 1 or a 2 i.e. 1/6 + 1/6 = 2/6 which simplifies to 1/3. The probability of getting a head when you flip a fair coin is 1/2. Both are independent events, so the probability of getting a number less than 3 and getting a head is 1/3 x 1/2 = 1/6. One can get the same answer from a sample space diagram
Any normal die contains three numbers that are less than 4 so the answer must be 1.
Probability can not be less than 0 or greater than 1. A probability of 0 means there is no possibility whatsoever of an event occurring. A probability of 1 means that the event is guaranteed to occur no matter what.
The probability of two events that are equally likely to occur is 0.5 or 50%, assuming there are only two possible outcomes. This means that each event has an equal chance of happening.
No. Probability must be between 0 and 1.
The probability of rolling a number less than 6 on a die would be 5/6.
No; because probability can never be less than zero.