This applies when 0 counts too:
10% * 10% * 10% * 10% = 0.01%
And when 0 is not a valid number:
11.11% * 11.11% * 11.11% * 11.11% = 0.015%
A three digit number can be chosen in 9*10*10 = 900ways No. of ways to choose a three digit number without 7 is 8*9*9 = 648 ways probability of picking a three digit number that includes atleast one digit that is 7 is 1- (648/900) = 252/900 = 7/25
It is possible to create a 3-digit number, without repeated digits so the probability is 1.
If 5 is a factor of a number, it means the number is divisible by 5. For the ones digit of the number to be 5, the number must end in 5. Since there are 10 possible digits (0-9), and only one of those digits is 5, the probability of the ones digit being 5 is 1 out of 10, or 1/10.
It is 1/10.
The number of license plates without a repeated letter or digit is 26x25x24x10x9 = 1 404 000. The number of license plates without any restriction is 26x26x26x10x10 = 1 757 600. Probability of a license plate without a repeated letter or digit = 1 404 000 /1 757 600 = 0.7988 Probability of a license plate with a repeated letter or digit = 1-0.7988 = 0.2022
40/50
A three digit number can be chosen in 9*10*10 = 900ways No. of ways to choose a three digit number without 7 is 8*9*9 = 648 ways probability of picking a three digit number that includes atleast one digit that is 7 is 1- (648/900) = 252/900 = 7/25
The probability is 1/2.
The probability is 1/2.
One out of a thousand^^^This is not quite true. If you must match them in order, then this is correct. However, if order does not matter (i.e. 4-5-6 is the same as 6-4-5), then the probability increases.The reason is that the probability is no longer 1/10*1/10*1/10, since this would assume that all three are unrelated. If order doesn't matter, then 4-5-6 = 6-4-5 = 5-4-6 = ... and so on, and all of these win. Thus, the answer is (all the different ways you can write the 3 digit number)/1000.
It is 0.45
It is 4/9
Well, honey, there are 90 two-digit numbers between 1 and 100, and a total of 100 numbers in that range. So, the probability of picking a two-digit number is 90/100, which simplifies to 9/10. So, the chances are pretty darn high, darling!
.9
162
8
The 4-digit Michigan evening lottery number drawn on May 24, 1983, was 3705. If you need more specific details or historical lottery data, it may be helpful to consult official Michigan lottery archives or resources.