Probability of a 3 on the first roll = 1/6
Probability of a 3 on the second roll = 1/6
Probability of both of them = (1/6) x (1/6) = 1/36 = 0.0277777 = 2.78% (rounded)
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Let A be the event of rolling a 4. P(A) = 1/6 P(A)P(A)=(1/6)(1/6)=1/36 Therefore, the probability of rolling a 4 twice with two rolls of a number cube is 1/36.
Because 3/6 of the sides on a number cube have even numbers, the probability of rolling even on one number cube is 1/2(equivalent of 3/6). But since you're rolling twice, you multiply the probability of one by itself (therefore rolling 2 number cubes). So: 1/2x1/2=1/4 The probability of rolling an even number when a number cube is rolled twice is 1/4, 25%, or 1 out of 4.
50 percent
The probability of rolling a seven with one roll of a standard number cube is zero.
1 out of 6