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To calculate the probability of drawing a black card and a 7 from a standard deck of 52 cards, we first determine the total number of black cards and the number of 7s in the deck. There are 26 black cards (13 spades and 13 clubs) and 4 sevens in the deck. The probability of drawing a black card and a 7 is calculated by multiplying the probability of drawing a black card (26/52) by the probability of drawing a 7 (4/52), resulting in a probability of (26/52) * (4/52) = 1/26 or approximately 0.0385.
the assessment step involves the application of quantitative or qualitative measures to determine the probability and severity of ill effects potentially resulting from exposure to a hazard
Independent. The chance the die are either a total of 11 or one will be a 4 are not related. --------------------------------------------------------------------------------------------- There are only two ways the sum of the resulting numbers of two dice thrown give 11: (5,6) and (6,5). The probability for event A is: P(A) = 2(1/6)(1/6) = 1/18 = 0.05555... ≈ 5.56% Given event A, there is no possibility that one of the two dice show a 4. The conditional probability is, P(B|A) = 0. So, event B is dependent of event A.
When flipping a coin, there are 2 possible outcomes. When flipping 3 coins there are 8 possible outcomes (2^3=8). As for the situation described, there is only one way for it to not be true, if all the coins land on the same side. So either all heads or all tails. This leaves 8-2=6 possible outcomes resulting in the above situation. Therefore the probability of the given situation is 6/8 or 3/4=75%
To determine the probability of different offspring from the cross of genotypes BB, Bb, and bb, we first need to clarify the specific cross being made. If we are crossing BB (homozygous dominant) with Bb (heterozygous), the potential offspring would be 50% BB and 50% Bb. If we then cross this with bb (homozygous recessive), the resulting offspring would be 50% Bb and 50% bb. Thus, the probabilities for the offspring would be 50% Bb and 50% bb.
1/6 or 16.66..%
1830
1830
1830
Most solids have a repeating pattern arrangement of particles in a crystalline structure. This structure allows the particles to maintain a regular and ordered arrangement, resulting in the solid having a distinct shape and volume.
A line of verse with four consecutive trochees is called a catalectic trochaic tetrameter line. This line consists of four trochees with the final trochee missing an unstressed syllable, resulting in a shortened line.
ans2. The probability of an even number resulting; from a large number of throws; would be 1/2. For 1/2 of the numbers 1 - 6 are even.
When a solid changes to a liquid, the particles gain enough kinetic energy to overcome the forces holding them in a fixed position. This causes the particles to break free from their fixed arrangement and move more freely, resulting in a less organized and more fluid arrangement.
The emission spectra for hydrogen and helium differ because each element has a unique arrangement of electrons in their atoms. This arrangement causes them to emit different wavelengths of light when excited, resulting in distinct spectral lines.
In a standard deck of 52 cards, there is only one ace of diamonds. The probability of drawing the ace of diamonds is 1 in 52, or ( \frac{1}{52} ). To find the probability against drawing it, you can subtract this probability from 1, resulting in ( 1 - \frac{1}{52} = \frac{51}{52} ). Therefore, the odds against drawing the ace of diamonds are 51 to 1.
Your question is slightly vague, so I will pose a more defined question: What is the probability of 3 coin tosses resulting in Tails exactly twice?The three possible (winning) outcomes are:TTHTHTHTTThe other (losing) outcomes are:HHHHHTHTHTHHTTTSo there is a 3 in 8 chance or a probability of 3/8 = 0.375
The word "mathematics" has 11 letters in total. The consonants in the word are m, t, h, m, t, c, and s, totaling 7 consonants. To find the probability of selecting a consonant, divide the number of consonants (7) by the total number of letters (11), resulting in a probability of 7/11.