This is a binomial distribution; number of trials (n) is 6, probability of success (p) is 1/2 or 0.5. With this information you can go to a Binomial Distribution Table and find the solution. Within the section of values for n=6 and p=.5, read from the section the probability of 2 which is 0.2344 (see related link for table).
Since a coin has two sides and it was tossed 5 times, there are 32 possible combinations of results. The probability of getting heads three times in 5 tries is 10/32. This is 5/16.
There is a 50% chance that it will land on heads each toss. You need to clarify the question: do you mean what is the probability that it will land on heads at least once, exactly once, all five times?
it is a fair chance so 1/2 :P
10 :)
It is 5/32 = 0.15625
3/8ths
3 out of 8
The answer depends on how many times the coin is tossed. The probability is zero if the coin is tossed only once! Making some assumptions and rewording your question as "If I toss a fair coin twice, what is the probability it comes up heads both times" then the probability of it being heads on any given toss is 0.5, and the probability of it being heads on both tosses is 0.5 x 0.5 = 0.25. If you toss it three times and want to know what the probability of it being heads exactly twice is, then the calculation is more complicated, but it comes out to 0.375.
Since a coin has two sides and it was tossed 5 times, there are 32 possible combinations of results. The probability of getting heads three times in 5 tries is 10/32. This is 5/16.
There is a 50% chance that it will land on heads each toss. You need to clarify the question: do you mean what is the probability that it will land on heads at least once, exactly once, all five times?
It is 3/4
0
10 :)
it is a fair chance so 1/2 :P
1/2
The odds are 50/50. A tossed coin does not have a memory.
It is 5/32 = 0.15625