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Since the first card is red, that eliminates all spades and clubs, leaving the hearts and diamonds. If the first card is replaced then the probability is 1/2. If the first card is not replaced then the probability is 12/25 if the first card is a heart, or 13/25 if the first card is a diamond
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JudyBad form on this question. The answer is impossible to determine because we don't know if the first card was a heart or not. The question should have been phrased "The second card is red given that the first card is a heart". In this better scenario, there are 51 remaining cards, 25 of the remaining ones are red, so the answer is 25/51.
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Out of a standard 52 card deck what is the probability of drawing a heart given that a red card was drawn first?
This is a conditional probability, given the card is red, what is the chance it is a heart. Since there are 2 red hearts, the probability if 1/2
What is the probability that the first card drawn is a spade given that the second card drawn is a spade?
It is 156/663 = 0.2353, approx.
What is The probability that the first and second card drawn from a deck of 52 cards are both kings?
Two cards are drawn from a pack of 52 cards second card is drawn after replacing the first card. What is the probability that the second card is a king?
What is the probability of drawing 2 hearts in a deck of cards?
Oh, dude, the probability of drawing 2 hearts from a deck of cards is like 1 out of 13 for the first card, and then 12 out of 51 for the second card. So, if you multiply those together, you get about a 4.5% chance of pulling off that heartwarming feat. But hey, who's counting, right?
If you select two cards from a deck of 52 cards what is the probability that the first card is an 6 of diamaond and the second card is an 3 of hearts?
First off, how do I calculate the probability that any one event occurs. The answer is equal to: Number of Possible Chances of Success / Total Number of Chances In this case, the number of possible chances of success is one (there is only one 6 of Diamonds in any deck of cards). The total number of chances equal 52 (there are 52 cards to choose from). Therefore the probability of picking a 6 of Diamonds on the first card is 1/52 or .019. In order to calculate the probability that the first card is a 6 of Diamonds AND the second card is a 3 of Hearts, you multiply the two probabilities. Prob. of 1st Card 6D AND 2nd Card 3H = Prob. 1st Card 6D * Prob. 2nd Card 3H We already know the probability of getting a 6 of Diamonds on the first card is 1/52 or .019. To calculate the probability of getting a 3 of Hearts on the second card, it is important to remember that random occurances do not affect the probability of other random occurrances. What I mean is, if I were to draw a 6 of Diamonds from a deck of cards and then replace it, the probability that I would pick a 6 of Diamonds again is the same as it was the first time. Even if I flip a coin 5 times in a row and they all landed on heads, the probability that I would flip another heads is still 50/50. So basically we can ignore what happened on the first draw, and jsut calculate the probability of getting a 3 of Hearts. Again we use our probability formula: Number of Possible Chances of Success / Total Number of Chances In this case, the number of possible chances of success is one (there is only one 3 of Hearts in any deck of cards). The total number of chances equal 52 (THIS ASSUMES THAT WE PUT THE 6 OF DIAMONDS BACK INTO THE DECK AFTER THE FIRST DRAW IF NOT THE NUMBER OF CHANCES IS 51). Therefore the probability of picking a 3 of Hearts on the second card is 1/52 or .019. Multiply the two probabilities together to get the probability of both occurring: 1/52 * 1/52 = 1/2704 = .00037 (or a .037 percent of a chance)
