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Since the first card is red, that eliminates all spades and clubs, leaving the hearts and diamonds. If the first card is replaced then the probability is 1/2. If the first card is not replaced then the probability is 12/25 if the first card is a heart, or 13/25 if the first card is a diamond
Bad form on this question. The answer is impossible to determine because we don't know if the first card was a heart or not. The question should have been phrased "The second card is red given that the first card is a heart". In this better scenario, there are 51 remaining cards, 25 of the remaining ones are red, so the answer is 25/51.
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Out of a standard 52 card deck what is the probability of drawing a heart given that a red card was drawn first?
This is a conditional probability, given the card is red, what is the chance it is a heart. Since there are 2 red hearts, the probability if 1/2
What is the probability that the first card drawn is a spade given that the second card drawn is a spade?
It is 156/663 = 0.2353, approx.
What is The probability that the first and second card drawn from a deck of 52 cards are both kings?
Two cards are drawn from a pack of 52 cards second card is drawn after replacing the first card. What is the probability that the second card is a king?
If you select two cards from a deck of 52 cards what is the probability that the first card is an 6 of diamaond and the second card is an 3 of hearts?
First off, how do I calculate the probability that any one event occurs. The answer is equal to: Number of Possible Chances of Success / Total Number of Chances In this case, the number of possible chances of success is one (there is only one 6 of Diamonds in any deck of cards). The total number of chances equal 52 (there are 52 cards to choose from). Therefore the probability of picking a 6 of Diamonds on the first card is 1/52 or .019. In order to calculate the probability that the first card is a 6 of Diamonds AND the second card is a 3 of Hearts, you multiply the two probabilities. Prob. of 1st Card 6D AND 2nd Card 3H = Prob. 1st Card 6D * Prob. 2nd Card 3H We already know the probability of getting a 6 of Diamonds on the first card is 1/52 or .019. To calculate the probability of getting a 3 of Hearts on the second card, it is important to remember that random occurances do not affect the probability of other random occurrances. What I mean is, if I were to draw a 6 of Diamonds from a deck of cards and then replace it, the probability that I would pick a 6 of Diamonds again is the same as it was the first time. Even if I flip a coin 5 times in a row and they all landed on heads, the probability that I would flip another heads is still 50/50. So basically we can ignore what happened on the first draw, and jsut calculate the probability of getting a 3 of Hearts. Again we use our probability formula: Number of Possible Chances of Success / Total Number of Chances In this case, the number of possible chances of success is one (there is only one 3 of Hearts in any deck of cards). The total number of chances equal 52 (THIS ASSUMES THAT WE PUT THE 6 OF DIAMONDS BACK INTO THE DECK AFTER THE FIRST DRAW IF NOT THE NUMBER OF CHANCES IS 51). Therefore the probability of picking a 3 of Hearts on the second card is 1/52 or .019. Multiply the two probabilities together to get the probability of both occurring: 1/52 * 1/52 = 1/2704 = .00037 (or a .037 percent of a chance)
What is the probability of picking 2 hearts at random from a deck of playing cards?
Chance of picking first heart card is 13/52, picking second right after is 12/51, total chance is 13/52 multiplied by 12/51. This works if we pick one card, don't replace it and then pick another. Here is the probability of 2 Hearts if we pick two cards at the same time. 13 Hearts choose 2/ 52 cards choose 2= 13C2/52C2=78/1326=1/17
Out of a standard 52 card deck what is the probability of drawing a heart given that a red card was drawn first?
This is a conditional probability, given the card is red, what is the chance it is a heart. Since there are 2 red hearts, the probability if 1/2
What is the probability that the first card drawn is a spade given that the second card drawn is a spade?
It is 156/663 = 0.2353, approx.
Given an experiment of drawing two cards from a standard deck of 52 where the first card is not replaced before the second card is drawn?
Draw from the bottom?
What is the probability that the first card is an an ace or the second card is black?
The answer depends on whether or not the first card is replaced before the second is drawn.
What card is the Knave of hearts?
The Jack of Hearts
In the card game Hearts can a player lay the jack of diamonds in the first hand?
Yes. In Hearts you have to throw a card of the same suit as the first card thrown if you have one. The first card to play in the game is always the two of clubs. If you did not have a club, you could throw a card of a different suit. However, you cannot throw a point card in the first round. This means you cannot throw a heart or the queen of spades. But the jack of diamonds would be legal.
Two cards are randomly chosen from a standard deck of 52 playing cards without replacement. What is the probability both cards will be hearts?
pr(success) = number_of_ways_of_success/total_number_of_ways. As the two selections are independent, multiply the probability that the first card is a heart by the probability the second card is a heart. There are 13 hearts and 52 cards in a deck → pr(1st card heart) = 13/52 = 1/4 After 1 card has been selected, there are 51 cards left and if the first was a heart, there are only 12 hearts left → pr(2nd card heart also) = 12/51 = 4/17 → pr(1st two heart) = pr(1st card heart) × pr(2nd card heart) = 1/4 × 4/17 = 1/17
What is The probability that the first and second card drawn from a deck of 52 cards are both kings?
Two cards are drawn from a pack of 52 cards second card is drawn after replacing the first card. What is the probability that the second card is a king?
What is the probability of picking are red card from a deck of cards?
Since half of the cards (26 of the 52) are a red card (hearts and diamonds) the odds are 1 in 2 (or 50%) that any given card will be red.
What is a card game named after a body part?
'Hearts'.
What card is given in fencing when the first offense is made in the second group of offenses?
If you mean when you say second group of offenses the second kind of offense you have made in the same bout, it should be a red card, if you have already collected a red or a yellow card. If you mean when you say second group of offenses a group of offenses you make in a different bout, it would be a yellow card, as red and yellow cards do not carry over to other bouts.
If The first card is an ace and the second is also an ace what the probility?
Just a straight deal, the first card will be an ace 4 times out of 52, the second card will be an ace 3 times in 51. The total odds will be 12 times in 2652.However in the question posed the first card is an ace so the probability is 1 in 1, so the second card being an ace will occur 3 times in 51.In the question , the first card is ACE, and second is also an ACE. Hence probability is 1in 1.How ever the question should be framed "What is the probabilty for getting first card An ACE and also Second card as An ACE"
