The volume is 8 cubic cm.
1.004 cm
IsothermConsider a surface:Definition:q0, q1, ..., qn = Surface area (cm-2) covered by 0, 1, ..., n layers of adsorbed molecules.At Equilibrium:q0 must remain constant. . Rate of Evaporation Rate of Condensation . . = from First Layer onto Bare SurfaceSimilarly, at equilibrium q1 must remain constant. . Rate of Condensation Rate of Condensation . . on the Bare Surface on the 1st Layer + = + Rate of Evaporation Rate of Evaporation from the second layer from the second layer . . . k1Pq0 + k-2q2 = k2Pq1 + k-1q1Substituting into (I) givesk-2q2 = k2Pq1Extending this argument to other layers,Definitions:Total surface area of the catalyst,Total volume of gas adsorbed on surfacewhere v0 is the volume of gas adsorbed on one square centimeter of surface when it is covered with a complete layer. . . .where vm is the volume of gas adsorbed when the entire surface is covered with a complete monolayer.From (I),If we assume that the properties of the 1st, 2nd, ... layers are equivalent, then,Similarly,q3 =xq2 =x2q1Generally,qi =xqi-1 =xi-1q1 =xi-1yq0 =cxiq0 {c=x/y}Substituting into (V),Now,Also, . . .At saturation pressure of gas P0, an infinite number of adsorbate layers must build up on the surface. From equation VII, for this to be possible,must be infinite. This means that at P0, x must equal 1. . . . g = P0(From definition of x) . . . x = P/P0Substituting into VII, we arrive at the recognized form of the BET isotherm,This can be rearranged to give,
4 mm
10
A 9 cm cube has a surface area of 486 cm2
The surface area of a cube with side lengths 52.5cm is 16,540cm2
A cube has 6 faces and each face is square, so the answer is 6*11*11 sq. cm.
The cube 3 cm on a side has the greater surface area.
The surface area is 403.44cm2
The surface area of a 7 cm cube is 294 cm2
34 squares
The surface area of the cube will be about 216cm2
216 squared cm
The surface area of a cube with sides of 4 cm is 6*42 square cm = 96 sq cm. The surface area of a cube with sides of 2 units is 6*22 square units = 24 sq units.
To find the surface area of a single cube, you calculate the area of each face (6 faces) and add them together. Each face has an area of 1 cm x 1 cm = 1 cm². Therefore, the surface area of one cube is 6 cm². If the stack consists of n cubes, the total surface area would be 6n cm².
2400cm2