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To find the solution, describe the events that will allow the same color draws which are WW or BB or YY. Since replacement is not stated, without replacement is assumed. So, we need probability of WW, BB, and YY (added together) which are (2/12*1/11) + (4/12*3/11) + (6/12*5/11) or (2/132 + 12/132 + 30/132) or 44/132 or1/3.

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Q: There are 2 White 4 Black and 6 Yellow balls in an urn If you select 2 balls what is the probability that they are the same color?
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