The probability of drawing one face card is 12 in 52. The probability of drawing the second face card, then, is 11 in 51. And so on, 10 in 50, 9 in 49, and 8 in 48. Since this is sequential probability, simply multiply the odds, giving (12/52)(11/51)(10/50)(9/49)(8/48) or (95040/311875200). I'l leave it to the reader to do the simple reduction to lowest terms.
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In my family,my dad,myself and my brother all share the same birthday.(9/11/24; 9/11/52; and 9/11/53). Also,my niece was born on 9/11/85.Three generations! Can anyone beat that?
If the number 8 is PUT BACK INTO the group after the first draw, the probability of drawing an 8 then a 2 from 11 numbers is: 0.8% or eight-tenths of a percent [reason #1]If the number 8 is REMOVED from the group after the first draw, the probability of drawing an 8 then a 2 from 11 numbers is: 0.9% or nine-tenths of a percent [reason #2]Reason # 1 :On the first draw, you have a 1 in 11 chance of drawing the 8 (9%) then on the second draw there is again a 1 in 11 chance of drawing the 2 (9%). So 9% x 9% = 0.8% or 8/10 % (or 0.008)Reason # 2 :On the first draw, you have a 1 in 11 chance of drawing the 8 (9%) then on the second draw you only have a 1 in 10 chance of drawing the 2 (10%). So 9% x 10% = 0.9% or 9/10 % (or 0.009) OR If the first ball is removed, the odds are 55 to 1.
First we find the probability of getting a 7. Of the 36 outcomes possible 6 result in a sum of 7, in other words 1/6. The probability of getting an 11 is 2/36 or 1/18. The probability of getting one or the other is the sum of the two, 8/36 or 2/9. The proability of getting neither is equal to the probability of getting anything other than 7 or 8. We find this value by subtracting 2/9 from 1. So the probability of not getting 7 or 11 is 7/9.
Here are the two for comparison;For 3 to 1 odds of winning;Probability of winning:0.25, or;Chance of winning:25%---------------------For 9 to 1 odds of winning;Probability of winning:0.1, or;Chance of winning:10%
If the odds against are 8 to 1, that means on the average you expect it to not happen 8 out of 9 times, and happen the other 1 time out of 9. 1 out of 9 is 1/9 = 11.1% probability that the event willoccur.
The probability of drawing one face card is 12 in 52. The probability of drawing the second face card, then, is 11 in 51. And so on, 10 in 50, 9 in 49, and 8 in 48. Since this is sequential probability, simply multiply the odds, giving (12/52)(11/51)(10/50)(9/49)(8/48) or (95040/311875200). I'l leave it to the reader to do the simple reduction to lowest terms.
26.47%
-- If you roll one single 6-sided cube . . . probability = 331/3%, odds = 1 in 3, or 2 to 1 against it. -- If you roll a pair of 6-sided cubes . . . probability = 27/9%, odds = 1 in 36, or 35 to 1 against it.
The probability of rolling a 7 with 2 dice is 6/36; probability of rolling an 11 is 2/36. Add the two together to find probability of rolling a 7 or 11 which is 8/36 or 2/9.
the answer is 11 over 9
9/11 + 8/11 = 9+8/11 = 17/11 = 16/11
9/11 − 3/11 = 6/11
9 over 11.
11/20 divded by 9/20 = 11/9
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