The question is incorrect since the mean of 45 57 0 and 3 is not 30. And the value of 45 is 45, whatever its mean when combined with other numbers. Similarly, the value of 57 is 57, whatever its mean when combined with other numbers; etc.
The mean deviation or absolute mean deviation is the sum of the differences between data values and the mean, divided by the count. In this case the MAD is 6.
mean= 100 standard deviation= 15 value or x or n = 110 the formula to find the z-value = (value - mean)/standard deviation so, z = 110-100/15 = .6666666 = .6667
The mean for the WISC, like the WAIS, is 100. The deviations from 100, or standard deviations, are 15.
Variance = 17.9047619 Standard Deviation = 4.23140188
15
The standard deviation is a number that tells you how scattered the data are centered about the arithmetic mean. The mean tells you nothing about the consistency of the data. The lower standard deviation dataset is less scattered and can be regarded as more consistent.
score of 92
(15/sqroot(9))=5 So it is 5
Standard deviation is a calculation. It I used in statistical analysis of a group of data to determine the deviation (the difference) between one datum point and the average of the group.For instance, on Stanford-Binet IQ tests, the average (or, mean) score is 100, and the standard deviation is 15. 65% of people will be within a standard deviation of the mean and score between 85 and 115 (100-15 and 100+15), while 95% of people will be within 2 standard deviations (30 points) of the mean -- between 70 and 130.
The mean deviation or absolute mean deviation is the sum of the differences between data values and the mean, divided by the count. In this case the MAD is 6.
mean= 100 standard deviation= 15 value or x or n = 110 the formula to find the z-value = (value - mean)/standard deviation so, z = 110-100/15 = .6666666 = .6667
3.898717738 is the standard deviation.
The mean for the WISC, like the WAIS, is 100. The deviations from 100, or standard deviations, are 15.
I would say in America the mean IQ is about 60 and the standard deviation is about 15, this is about true for all ages.
Variance = 17.9047619 Standard Deviation = 4.23140188
IQ is distributed normally, with a mean of 100 and a standard deviation of 15. The z-score of 100 is therefore:(value-mean)*standard deviation= (100-100)*15= 0More generally, a raw score that is equivalent to the mean of a normal distribution will always have a z-score of 0.
15