No they are not the same.
degrees of freedom
Computing F-ratioThe F-ratio is used to determine whether the variances in two independent samples are equal. If the F-ratio is not statistically significant, you may assume there is homogeneity of variance and employ the standard t-test for the difference of means. If the F-ratio is statistically significant, use an alternative t-test computation such as the Cochran and Cox method.
In ANOVA, what does F=1 mean? What are the differences between a two sample t-test and ANOVA hypothesis testing? When would you use ANOVA at your place of employment, in your education, or in politics?
Let X(t) be an iid random process and hence X(t) has an identical distribution for any t i.e., distributions are identical at instants of time t1, t2...tn, so 1st order pdfs f(x1;t1), f(x2;t2)....f(xn;tn) are time invariant and further X(t1) and X(t2) are independent for any two different t1 and t2. So, f(x1, x2, . . . , xn; t1, t2, . . . , tn) = f(x1;t1)*f(x2;t2)*....*f(xn;tn) f(x1;t1), f(x2;t2).... f(xn;tn) are time invariant, therefore their product f(x1, x2, . . . , xn; t1, t2, . . . , tn) is also time invariant which is nth order pdf. So X(t) is strict sense stationary.
This is a Ditloid. The answer is 11 Players on a Football Team.
11 players in a football (Soccer) team
It means the answer is -11p.
tit festy tit
T = tablespoont = teaspoont= the f word
5 T on the F means 5 Toes on the Foot
OTTFF stands for the first five numbers.OneTwoThreeFourFive
2p + 11p + 5 = 13p + 5 which does not factor. If the expression had been 2p2 + 11p + 5 then this can be factored, 2p2 + 11p + 5 = (2p + 1)(p + 5)
what freaking time
88 is two fat ladies in bingo
Do you mean f(t) = -16t^2 - 48t + 160? This is a function, which can't be "solved" as it is. - you could factor it: -16(t + 5)(t - 2) - you solve for f(t) = 0: t = 2, -5