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that its old, fresh urine samples are usually between those temperatures. So if taking a drug test it can spotted that someone may have brought in someone else's urine because it isn't hot/fresh

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Compute the population mean margin of error for a 90 percent confidence interval when sigma is 4 and the sample size is 36?

1.0966


What is the null hypothesis of an overall mean for a score of 85 with a standard deviation of 10 and the mean for 40 students is 90.?

The null hypothesis could be that the 40 students are a sample from the same (or similar) population.


What is the mean median and mode of 60 70 75 78 80 80 83 85 87 90 90 90 90 93 95 95 98 100?

The mean is 85.5 The median is 88.5 The mode is 90


What is the mean for 80 85 76 70 87 80 90 80 90?

82.


How do you calculate mean absolute deviation?

The Mean Absolute Deviation is calculated in three simple steps.1) Determine the Mean: Add all numbers and divide by the countexample: the weights of the following three people, denoted by letters areA - 56 KgsB - 78 KgsC - 90 KgsMean = (56+78+90)/3= 74.62) Determine deviation of each variable from the Meani.e 56-74.6 = -18.6778-74.6= 3.3390-74.6 =15.333) Make the deviation 'absolute' by squaring and determining the roots i.e eliminate the negative aspectThus the Mean Absolute Deviation is (18.67 +3.33+15.33)/3 =12.44Alternatively , you can use the excel formula =AVEDEV(56,78,90) to obtain the result.Different MethodsThere are different formulas for the calculation of mean absolute deviation. For example mean absolute deviation from mean and mean absolute deviation from median. Similarly the formulas for grouped and ungrouped data are also different. In order to see the calculation of mean absolute deviation from mean and mean absolute deviation from median for both grouped and ungrouped data please visit the link given below.Let's consider the sample {2, 2, 3, 4, 14}.First of all you must decide, what am I calculating the mean absolute deviation from? Will it be the mean, the mode or the median? (It could be any measure of what statisticians call 'location' or 'central tendency'.)For no good reason except that it's familiar to most people let me choose the mean of the sample. It proves to be 5.Now we need the absolute deviation of each sample element from the mean. Notice that these are the distances between the mean and the sample elements.|2 - 5| = |-3| = 3|2 - 5| = |-3| = 3|3 - 5| = |-2| = 2|4 - 5| = |-1| = 1|14 - 5| = |9| = 9The sum of these is 18; then their average is 18/5 = 3.6. So the mean absolute deviation (from the mean) is 3.6. In other words, the sample points are, on average 3.6 units from the mean.For more information visit the Related Links.

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