1.0966
The null hypothesis could be that the 40 students are a sample from the same (or similar) population.
The mean is 85.5 The median is 88.5 The mode is 90
82.
The Mean Absolute Deviation is calculated in three simple steps.1) Determine the Mean: Add all numbers and divide by the countexample: the weights of the following three people, denoted by letters areA - 56 KgsB - 78 KgsC - 90 KgsMean = (56+78+90)/3= 74.62) Determine deviation of each variable from the Meani.e 56-74.6 = -18.6778-74.6= 3.3390-74.6 =15.333) Make the deviation 'absolute' by squaring and determining the roots i.e eliminate the negative aspectThus the Mean Absolute Deviation is (18.67 +3.33+15.33)/3 =12.44Alternatively , you can use the excel formula =AVEDEV(56,78,90) to obtain the result.Different MethodsThere are different formulas for the calculation of mean absolute deviation. For example mean absolute deviation from mean and mean absolute deviation from median. Similarly the formulas for grouped and ungrouped data are also different. In order to see the calculation of mean absolute deviation from mean and mean absolute deviation from median for both grouped and ungrouped data please visit the link given below.Let's consider the sample {2, 2, 3, 4, 14}.First of all you must decide, what am I calculating the mean absolute deviation from? Will it be the mean, the mode or the median? (It could be any measure of what statisticians call 'location' or 'central tendency'.)For no good reason except that it's familiar to most people let me choose the mean of the sample. It proves to be 5.Now we need the absolute deviation of each sample element from the mean. Notice that these are the distances between the mean and the sample elements.|2 - 5| = |-3| = 3|2 - 5| = |-3| = 3|3 - 5| = |-2| = 2|4 - 5| = |-1| = 1|14 - 5| = |9| = 9The sum of these is 18; then their average is 18/5 = 3.6. So the mean absolute deviation (from the mean) is 3.6. In other words, the sample points are, on average 3.6 units from the mean.For more information visit the Related Links.
The normal range for urine sample temperature is between 90-100°F (32-38°C). If the temperature is outside this range, it may suggest that the sample has been tampered with or is not from the donor's body. If the temperature is too high or too low, the sample may be considered invalid.
yes, if you mean 90 degrees is directly from above.
90 degree angles.90 degree angles.90 degree angles.90 degree angles.
An angle less than 90 degree's.
A triangle with a 90 degree angle.
if you mean acute then less than 90 degree angle
It means that in it less than 90 degree angle
90 degree comes to poles.there is no living habitate in 90 degree N and 90 degree East
Depends on what you mean by compliment. If its the compliment to a 90 degree angle it would be 42 degrees.
Did you mean "degree"? There are 90 degrees in a right angle.
A 90 degree angle
A 90 degree angle is a right angle.