http://wiki.answers.com/Q/If_you_Flip_four_coins_at_once_what_is_probability_of_2_head_and_3_tail" The probability of flipping four coins and getting 2 heads and 3 tails is ZERO 2 heads and 3 tails requires flipping FIVE coins.
Each coin toss is a Bernoulli trial with a probability of success of .5. The probability of tossing heads exactly 3 times out of five is3 ~ Bin(5, 1/2), which equals(5!/(3!(5-3)!))(0.5^3)(1-0.5)^(5-3), which is 0.3125.
The probability is 0.
Firstly, the probability when tossing a coin and getting a head or tail is 1/2, then rolling a die, there are 6 sides so the chance of rolling any number is 1/6, there are 2 chances of rolling greater than 4 ie 5 and 6, so the probability of rolling a 5 or 6 in 1/3, as these are independent events you multiply the probability getting a heads of tails, (1/2) by the probability of rolling a five or six, (1/3) which gives you 1/6 or 0.1666 recurring.
The probability of getting five tails in a row is 1/2^5, or 1 in 32.The probability of getting five heads in a row is 1/2^5, or 1 in 32.Thus, the probability of getting either five heads or five tails in five tosses is 1 in 16.(The caret symbol means "to the power of," as in 2^5 means "2 to the 5th power.")
The probability that you will toss five heads in six coin tosses given that at least one is a head is the same as the probability of tossing four heads in five coin tosses1. There are 32 permutations of five coins. Five of them have four heads2. This is a probability of 5 in 32, or 0.15625. ----------------------------------------------------------------------------------- 1Simplify the problem. It asked about five heads but said that at least one was a head. That is redundant, and can be ignored. 2This problem was solved by simple inspection. If there are four heads in five coins, this means that there is one tail in five coins. That fact simplifies the calculation to five permutations exactly.
http://wiki.answers.com/Q/If_you_Flip_four_coins_at_once_what_is_probability_of_2_head_and_3_tail" The probability of flipping four coins and getting 2 heads and 3 tails is ZERO 2 heads and 3 tails requires flipping FIVE coins.
Each coin toss is a Bernoulli trial with a probability of success of .5. The probability of tossing heads exactly 3 times out of five is3 ~ Bin(5, 1/2), which equals(5!/(3!(5-3)!))(0.5^3)(1-0.5)^(5-3), which is 0.3125.
The probability is 0.
Firstly, the probability when tossing a coin and getting a head or tail is 1/2, then rolling a die, there are 6 sides so the chance of rolling any number is 1/6, there are 2 chances of rolling greater than 4 ie 5 and 6, so the probability of rolling a 5 or 6 in 1/3, as these are independent events you multiply the probability getting a heads of tails, (1/2) by the probability of rolling a five or six, (1/3) which gives you 1/6 or 0.1666 recurring.
The probability of getting five tails in a row is 1/2^5, or 1 in 32.The probability of getting five heads in a row is 1/2^5, or 1 in 32.Thus, the probability of getting either five heads or five tails in five tosses is 1 in 16.(The caret symbol means "to the power of," as in 2^5 means "2 to the 5th power.")
It is 0.3125
It is 5/32 = 0.15625
The probability of getting five heads out of 10 tosses is the same as the probablity of getting five tales out of ten tosses. One. It will happen. When this happens, you will get zero information. In other words, this is the expected result.
There is a 50% chance that it will land on heads each toss. You need to clarify the question: do you mean what is the probability that it will land on heads at least once, exactly once, all five times?
The probability of any 1 result of tossing a coin 5 times, for example HHTHH or TTTTH, is 1/2^5 = 1/32. To find out how many of these results involve getting 3 heads, say HHHTT or HHTHT, we use the calculation 5!/(3!*2!), which = 10. Finally we multiply these 2 results to get 10/32 = 5/16.
The probability of getting all heads or all tails in 5 flips of a coin is 1 in 16.The probability of getting a head or a tail on the first flip is 1 in 1. The probability of each of the following coins matching the first coin is 1 in 2. Simply multiply the five probabilities (1 in 1) (1 in 2) (1 in 2) (1 in 2) (1 in 2) and you get 1 in 16.It is true that the probability of getting all heads is 1 in 32, and the probability of getting all tails is also 1 in 32. Since the question asked the probability of both cases (all heads or all tails), the answer is 1 in 16.