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What is probability of obtaining a number different from 12 when a single fair die is tossed?
assuming we are talking about standard dice here (six sided, numbered 1-6) then the probability of obtaining a result other than 12 when a single die is tossed is 100%. There is no way to roll a 12 after 1 toss of 1 die, therefore the chance of getting anything other than 12 is guaranteed
Two dice a tossed find the probability that the numbers are the same given that at least one is 3?
There are two different ways to look at this that give two different answers. The first way is this. We already know that one of the dice is a three. So the question of whether the two dice show the same number becomes "Is the second die a 3?" And the probability of the second die being a 3 is 1/6. Without really making it clear, this method ASSUMES that it is the FIRST die that is constrained to be a 3. The other way is this. The question constrains AT LEAST ONE of the two die to be a 3, but we don't know which one. So, what you have to do is draw a chart, listing all the possibilities (1-6) for die #1 on the left and all the possibilities for die #2 (also 1-6)across the top. There are 36 possible outcomes. But in only 11 of them does EITHER of the two dice show a 3. And, among those 11, in only 1 does BOTH dice show a 3. Therefore, the probability is 1/11.
How many ways can you die?
There are 1000 ways to die.
What is the probability of rolling a dice 7?
With a single throw of a normal die, the probability is 0.With a single throw of a normal die, the probability is 0.With a single throw of a normal die, the probability is 0.With a single throw of a normal die, the probability is 0.
What is the complement of rolling a die and getting a 4?
The complement of rolling a die and getting a 4 is rolling a die and getting a 1, 2, 3, 5, or 6.
