Perimeter = area + b1 + b2 + c
P = a + b1 + b2 + c
A hexagonal prism is a polyhedron with two parallel bases bounded by congruent hexagons and with lateral faces bounded by parallelograms that connect corresponding sides of the bases. The height h of the prism is any perpendicular segment drawn from a point on the base to the plane containing the other base. If the segments that join corresponding vertices of the bases are perpendicular to the bases, then the prism is a right hexagonal prism. Otherwise, it is called oblique. The perimeter formula of a right regular hexagonal prism is P = 12s + 6h where s = side and h = height
A pentagonal prism * * * * * No. A pentagonal prism has 7 faces and 10 vertices! A rectangular pyramid has 5 faces and 5 vertices.
(1)Best formula to use is as follows -V = h/3(Areatop + √(Areatop*Areabottom) + Areabottom)(2)To find (h) using a tape measure -Areatop => bdAreabase => acLateral edge remaining => e (from top corner to base corner)k = 1 - √(bd/ac)H= √([e/k]² - [a/2]² - [c/2]²)h = HkV = H/3*(ac-bd+bd*k)(3)Lets say Top is a rectangle with sides b & dand bottom is a rectangle with sides a & c respectively.Let height be hin that case the volume of Truncated Pyramid with rectangular base will be -V = 1/3((a²c-b²d)/(a-b))hBUT BE CAREFUL - a,b,c,d are not all independent variables (one depends on the others) so this answer is misleading!!!Proof -Suppose the height of Full Pyramid is HFrom parallel line property(H-h)/H = b/aRearrangingH = ah/(a-b) --------------------(1)AlsoSince V=1/3 Base area X HeightVolume of full pyramid = 1/3 X ac X HVolume of removed Pyramid = 1/3 X bd X (H-h)So volume of truncated part V = 1/3(acH-bd(H-h))=1/3((ac-bd)H + bdh)From (1)V = 1/3((ac-bd)ah/(a-b) + bdh)reducing and rearranging we getV = 1/3((a²c-b²d)/(a-b))h(4)In case the truncated solid forms a prism instead, we have following formula -V = ( h/6)(ad + bc + 2ac + 2bd)Proof -Fig(1)Fig(2)Lets divide the fig(1) into four different shapes as shown in fig(2)VA = Volume of cuboid = bdhVB = Volume of prism after joining both Bs= ½ X base X height X width = ½ (a-b) (d)(h)VC = Volume of prism after joining both Cs = ½ X base X height X width = ½ (c-d) (b)(h)VD = Volume of rectangular pyramid after joining all Ds = 1/3 X base area X height =1/3 (a-b) (c-d) hThen V = VA + VB + VC + VDOr, V = bdh + 1/2(a-b)dh +1/2(c-d)bh + 1/3(a-b)(c-d)hArranging and simplifying we get -V = ( h/6)(ad + bc + 2ac + 2bd)
You must be thinking of a triangular prism. In that case, c is the length of the third side of the triangle at the end of the prism.
area of base x height area of base x height
The total surface area of a trapezoidal prism can be calculated using the formula ( A = (b_1 + b_2)h + P \cdot l ), where ( b_1 ) and ( b_2 ) are the lengths of the two bases of the trapezoid, ( h ) is the height of the trapezoid, ( P ) is the perimeter of the trapezoidal base, and ( l ) is the length (or height) of the prism. This formula accounts for the area of the two trapezoidal bases and the lateral surfaces connecting them. Make sure to substitute the appropriate values to find the total surface area.
I dont know:d
There must be a typo in this question, "Why does the formula for finding the surface area of arectangular prism is helpful?" What does that even mean?
its not i dont no why
Volume = 1/2*(a+b)*h*l where a and b are the lengths of the parallel sides of the trapezium, h is the height of the trapezium, and l is the length of the prism.
If you mean volume of a trapezoidal prism then it is: 0.5*(sum of parallel sides)*height*length
I am not sure that a rectangular prism is in any position to care!
the volume of a trapezoidal prism is equal to the height times the base area of the trapezoid. First you find the area of trapezoid h(a+b)/2 h is the height of the trapezoid, not the height of the prism a is the length of the top b is the length of the bottom Then you find the volume of the trapezoidal prism with this formula H*h(a+b)/2 H is the height of the prism. Multiply H by the area of the trapezoid that you found in step one.
Surface Area = 2 × Base Area + Base Perimeter × Length
A trapezoidal prism has 8 vertices:A trapezoid has 4 vertices.A trapezoidal prism is composed of 2 trapezoids. 2 X 4 = 8.