Mean: 11.6
Median: 12
Mode: 10, 12, 15, 16, 5
Range: 11
what i have is mean is 22.2,median which is the middle is 23,range is 26, and mode is 12
5, 6, 9, 10, & 10
The average, median and mode of a list of numbers will be the same when the middle (or mean of the two middle numbers) is equal to the most common number in the list, and that number is also the mean. This assumes that the list has only a single mode. If you arrange such a list of numbers from least to greatest, the mode value will be grouped at the middle of the list, thus becoming the median as well. The average of the non-median values will be equal to the median/mode. Given a target mean/median/mode and a list length, you can construct an infinite number of lists that qualify. Here are some examples: 10 10 10 10 10 (or any list of only one number) 11 12 12 12 12 13 1 2 3 4 5 5 5 6 7 8 9
I am guessing you are asking for an example of a set of numbers with these properties. Let's start with 5 numbers, so the median will be the middle number; say 1, 2, 3, 4, 5. The median is 3, but so is the mean. Now let's replace the 5 with 10. The median is still 3, but the mean is 4. To make the mode less than 3, let us change the 2 into a 1. Now the median is still 3, the mode is 1, and the mean is 3.8. So 1, 1, 3, 4, 10 will work.
The median is the middle number of any given set when they are in order, least to greatest. If there is an even number of values, the median is the average of the middle two. Ex. (10, 17, 20, 45, 68) The median is 20. In any given set, the mode is the number that appears most often. If no number appears more frequently than any other, there is no mode. Ex. (10, 17, 20, 45, 68) This set has no mode. In any given set, the mean is the average, which is the total of the numbers divided by how many numbers there are. Ex. (10, 17, 20, 45, 68) 68 + 45 + 20 + 17 + 10 = 160 There are 5 numbers in this set. 160/5 = 32 The mean is 32.
Range: 34 Mean: 21.71 Median: 15 Mode: 10
Range: 25 Mean: 10 Median: 11 Mode: 11, 1
There cannot be such a set.If the mean is 10, the mode is 6 and the median is 9, the range must be at least 8.5.If the mode is 6, the median is 9 and the range is 8, the mean must be less than 9.8.
Mean: 7.44 Median: 7 Mode: 7 Range: 7
8, 8, 8, 10, 14, 15 The mean is 10.5 The median is 9. The mode is 8. The range is 7.
Mean: 20.2222222 Median: 12 Mode: 11 Range: 79
what i have is mean is 22.2,median which is the middle is 23,range is 26, and mode is 12
mean: 9 ordered sample: 7, 8, 8, 10, 12 median: 8 mode: 8 range: 12 - 7 = 5
mean=19.1 median=18 mode=18 range=10 there are websites all over that help with this stuff just Google how to find mode mean range and median and you will get tons of results
5, 6, 9, 10, & 10
The mean is 6.6. The median is 6. There is no mode.
I'm going to guess that's the set (5, 5, 6, 7, 8, 8, 10, 10, 10, 12) Sum: 81 Mean: 8.1 Mode: 10 Range: 7