The median of a set of numbers is the middle number when they are laid out in numerical order. When there is an even amount of numbers in the sequence like this one, there are two numbers in the middle. To find out the median from these two numbers, you just need to find the average of the two numbers. As the two numbers in the middle of this set of numbers is 53 and 54, the average is 53.5. This means that the median of this set of numbers is 53.5.
You put the numbers in order. As there are 8 numbers, and even amount, the median is halfway between the two middle numbers. In this case, that is 61 and 76. The median is therefore 68.5 as it is halfway between them, or the result if you add them and divide by 2.
The median is 50. Put the numbers in ascending numerical order: 40 45 48 52 61 65 For a set of numbers with an odd number of observations, the median would simply be the middle number. Because this set of numbers has an even number of observations, we take the middle two observations (48 and 52) and find their average. To find the average you add the observations and divide by the number of observations. In this case you would take 48 added to 52 and divide the sum of these numbers by 2. This gives you an answer of 50. (48 + 52 = 100 / 2 = 50)
The first step in constructing a box-and-whisker plot is to first find the median, thelower quartile and the upper quartile of a given set of data. Example: The following set of numbers are the amount of marbles fifteen different boys own (they are arranged from least to greatest).18 27 34 52 54 59 61 68 78 82 85 87 91 93 100First find the median. The median is the value exactly in the middle of an ordered set of numbers. *68 is the medianNext, we consider only the values to the left of the median: 18 27 34 52 54 59 61. We now find the median of this set of numbers. Remember, the median is the value exactly in the middle oa an ordered set of numbers. Thus 52 is the median of the scores less than the median of all scores, and therefore is the lower quartile.52 is the lower quartileNow consider only the values to the right of the median: 78 82 85 87 91 93 100. We now find the median of this set of numbers. The median 87 is therefore called the upper quartile.87 is the upper quartile(*If you're finding the median in an ordered set with an even number of values, you must take the average of the two middle numbers. For example: 3, 5, 7, and 10. Add the two middle numbers. 5 + 7 = 12. Divided 12 by 2 to get the average. 12 / 2 = 6. Therefore 6 is the median for the ordered set of 3, 5, 7, and 10.)You are now ready to find the interquartile range (IQR).The interquartile range is the difference between the upper quartile and the lower quartile. In our case the IQR = 87 - 52 = 35. The IQR is a very useful measurement. It is useful because it is less influenced by extreme values, it limits the range to the middle 50% of the values.35 is the interquartile rangehere is a sucessful site called Jen's Box and Whisker plot, and here is a example of a whisker plot from that very own site. because itso hard to describe! i hope you find this helpful good luck!!
The sample space of a standard six sided die rolled twice, or two dice rolled once (they are the same) is [11, 12, 13, 14, 15, 16, 21, 22, 23, 24, 25, 26, 31, 32, 33, 34, 35, 36, 41, 42, 43, 44, 45, 46, 51, 52, 53, 54, 55, 56, 61, 62, 63, 64, 65, 66].
The sample space is:11, 12, 13, 14, 15, 16, 21, 22, 23, 24, 25, 26, 31, 32, 33. 34, 35, 36, 41, 42, 43, 44, 45, 46, 51, 52, 53, 54, 55, 56, 61, 62, 63, 64, 65, 66. P(Alana wins) = 1/36 if the dice are fair.
Range: 24 Median: 59.5 Mode: 57, 61, 58, 54, 68, 51, 65, 75
order from small to large and its the one in the middle: 76
You put the numbers in order. As there are 8 numbers, and even amount, the median is halfway between the two middle numbers. In this case, that is 61 and 76. The median is therefore 68.5 as it is halfway between them, or the result if you add them and divide by 2.
All the prime numbers between 50 and 75 are 53, 59, 61, 67, 71 and 73.
ANSWER: 311First five prime numbers after 50: 53, 59, 61, 67, 71Sum = 53 + 59 + 61 + 67 + 71 = 311
53, 59 and 61.
53 59 61 67.
All the prime numbers 50 through 75 are: 53, 59, 61, 67, 71, and 73.
The number between 53 and 61 is 57. To find the number between two given numbers, you would typically calculate the average of the two numbers. In this case, (53 + 61) / 2 = 57.
53 61 67 71 and 73
53 59 61 67.
They are: 53 59 and 61