Mean: 5 Median: 5 Mode: 3
Mean: 7 Median: 6 Mode: 1, 9, 4, 7, 5, 3, 16, 11
The mean is the average of the numbers when they are added together and divided by the total numbers given. For example, start with the numbers 1, 3, 5, 7, 9. Add them together to get 25. Divide by 5 because that is how many numbers are listed. The mean is 5. The median is the number in the middle. In this case, the 5 is in the middle, so it is the median. If these numbers, 1, 3, 5, 7 were listed, none of them are exactly in the middle, so the median would be the average of 3 and 5, or 4. The mode is the number that appears the most often. In this case, each number appears only once, so there is no mode. If these numbers were listed, 4. 5, 5, 6, 7, 7. 7 were listed, 7 occurs the most, so it would be the mode. If two or more numbers are listed more than once the same amount of times, the numbers listed the same amount of times are the modes. For example: 4, 5, 5, 5, 6, 7, 7, 7: both 5 and 7 would be the modes.
To find the mean you add all the numbers together then divide by how many there are. Ex. 5+10+6+6+5+12+5=49 49/7=7 Mean=7 To find the median you put the numbers from least to greatest the find the number in the middle. (note: if there are two numbers in the middle add hem and divide by two.) Ex. 5,5,5,6,6,10,12 Median:6 To find the mode you look for the number that appears the most. (note: There can be more than one mode or there can be no mode) Ex. 5,5,5,6,6,10,12 Mode:5
The mean of those seven numbers is (5 + 9 + 6 + 6 + 11 + 8 + 4)/7 = 7 The median of those seven numbers is 6. The mode of those numbers - the only number which appears more than once - is 6.
3 occurs most often, so it is the mode.
Mean: 5 Median: 5 Mode: 3
There is no mode.
5
There is no mode in this list.
Median: 3 Mode: 1 Range: 6
That set has no mode.
5
With extreme difficulty, that is, you cannot.The mode depends entirely upon the data items and the same mode can be found for different pairs of means and medians; similarly for any given pair of mean and median, there are many modes possible.example:The data sets {1, 1, 3, 4, 5, 6, 7, 8, 10}:mean: (1 + 1 + 3 + 4 + 5 + 6 + 7 + 8 + 19) ÷ 9 = 6median: [1, 1, 3, 4] , 5, [6, 7, 8, 19] = 5mode: [1, 1], 3, 4, 5, 6, 7, 8, 19 = 1and {1, 2, 3, 4, 5, 6, 7, 7, 19}:mean: (1 + 2 + 3 + 4 + 5 + 6 + 7 + 7 + 19) ÷ 9 = 6median: [1, 2, 3, 4], 5, [6, 7, 7, 19] = 5mode: 1, 2, 3, 4, 5, 6, [7, 7], 19 = 7both have mean 6 and median 5, but the first has a mode of 1 and the second a mode of 7 - you cannot tell the mode from the mean and median.
Mean: 7 Median: 6 Mode: 1, 9, 4, 7, 5, 3, 16, 11
Mean 5 Median 7.5 Mode 5 Range 4
12