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How many permutations of letters in word swimming?
The number of permutations of the letters SWIMMING is 8 factorial or 40,320. The number of distinct permutations, however, due to the duplication of the letters I and M is a factor of 4 less than that, or 10,080.
How many permutations of the letters in the word Louisiana are there?
The number of permutations of the letters in the word LOUISIANA is 9 factorial or 362,880. However, since the letters I and A are each repeated once, you need to divide that by 4 to determine the number of distinct permutations, giving you 90,720.
How many permutations are in the word mathematics?
The word MATHEMATICS has 11 letters. The number of permutations of 11 things taken 11 at a time is 11 factorial (11!), or 39,916,800.
How many permutations are there for the letters in the word LOLLIPOP?
LOLLIPOP = 8 letters L=3 O=2 I=1 P=2 number of permutations = 8!/3!2!2! = 8x7x6x5x4x3x2 / 3x2x2x2 = 40320 /24 = 1680
How many ways can the letters abcdef be arranged?
The number of permutations of the letter ABCDEF is 6 factorial, or 720.
How many distinguishable permutations are there of the letters of the word rectangle?
The word "rectangle" consists of 9 letters, with the letter 'e' appearing twice and all other letters being unique. To find the number of distinguishable permutations, we use the formula for permutations of a multiset: (\frac{n!}{n_1! \cdot n_2! \cdots n_k!}), where (n) is the total number of letters and (n_i) are the frequencies of the distinct letters. Thus, the number of distinguishable permutations is (\frac{9!}{2!} = \frac{362880}{2} = 181440).
How many distinguishable and indistinguishable permutations are there in the word algrebra?
The word "algrebra" has 8 letters, with the letter 'a' appearing twice and 'r' appearing twice. To find the number of distinguishable permutations, we use the formula for permutations of multiset: ( \frac{n!}{n_1! \times n_2!} ), where ( n ) is the total number of letters and ( n_1, n_2 ) are the frequencies of the repeating letters. Thus, the number of distinguishable permutations is ( \frac{8!}{2! \times 2!} = 10080 ). Since all letters are counted in this formula, there are no indistinguishable permutations in this context.
In how many ways can all the letters in the word mathematics be arranged in distinguishable permutations?
The word mathematics has 11 letters; 2 are m, a, t. The number of distinguishable permutations is 11!/(2!2!2!) = 39916800/8 = 4989600.
What is the number of distinguishable permutations of the letters in the word oregon?
360. There are 6 letters, so there are 6! (=720) different permutations of 6 letters. However, since the two 'o's are indistinguishable, it is necessary to divide the total number of permutations by the number of permutations of the letter 'o's - 2! = 2 Thus 6! ÷ 2! = 360
Find the number of distinguishable permutations of letters in the word appliance?
The distinguishable permutations are the total permutations divided by the product of the factorial of the count of each letter. So: 9!/(2!*2!*1*1*1*1*1) = 362880/4 = 90,720
How many distinguishable permutations are there of the letters in the word effective?
The number of permutations of the letters EFFECTIVE is 9 factorial or 362,880. To determine the distinct permutations, you have to compensate for the three E's (divide by 4) and the two F's (divide by 2), giving you 45,360.
Find the number of distinguishable permutations of the letters honest?
It is 6! = 6*5*4*3*2*1 = 720
Find the number of distinguishable permutations of the letters in the word manatee?
Take the total number of letters factorial, then divide by the multiple letters factorial (a and e). 7! / (2!*2!) or 1260.
What is the number of distinguishable permutations?
The formula for finding the number of distinguishable permutations is: N! -------------------- (n1!)(n2!)...(nk!) where N is the amount of objects, k of which are unique.
What are number of distinguishable permutations in the word Georgia?
2520.
How may distinguishable permutations are possible with all the letters of the word ellises?
We can clearly observe that the word "ellises" has 7 letters and three pairs of letters are getting repeated that are 'e','l' and 's'. So, Number of distinguishable permutations = 7!/(2!2!2!) = 7 x 6 x 5 x 3 = 630.
What is the number of distinguishable permutations of the letters in the word EFFECTIVE?
The number of permutations of the letters EFFECTIVE is 9 factorial or 362,880. Since the letter E is repeated twice we need to divide that by 4, to get 90,720. Since the letter F is repeated once we need to divide that by 2, to get 45,360.
