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What is the probability of 4 boys in a family with 4 children?
In a family with four children, the probability of having four boys is 1 in 16.
In a family of four children what is the probability of having exactly two daughters assuming sons and daughters are equally likely?
50-50
What is the probability that a couple would have a family of four children two boys and two girls and in that order?
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52 in all cases, the overall probability is 0.0624.
What is the probability of rolling a four on an eight sided die numbered from one to eight?
The probability of rolling a four on an eight sided octahedron is 1 in 8, or 0.125.
Probability of having a boy or a girl?
The probability of having a boy or a girl is always 50/50 because the female has to X sex chromosomes and the male has one X and one Y sex chromosome. If you do a Punnet Square, there will be two squares with XY and two squares with XX. With four squares in all that makes a 50/50 chance.
What is the probability of 4 boys in a family with 4 children?
In a family with four children, the probability of having four boys is 1 in 16.
What is the probability of a family having a boy after four girls?
The probability of a boy is still 0.5 no matter how many prior children there are.
What is the probability of flipping 2 coins and having both show heads?
If both tosses are fair, the probability of that outcome is one in four.
What is the probability that a family with four children has all boys given that the first two are boys?
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of the other two being boys is 0.2672.
What is the probability of a couple having at least four girls if they have six children?
3 out of 7
If 8 women are pregnant what is the probability that there will be 4 boys and what is the probability that at least 7 girls will be born?
Assuming that the probability of 1 woman have a boy is .5 Binomial Distribution can be used to solve the problem. b(k;n,p) = (n choose k) p^k * (1-p)^(n-k) k= number of boys n= number of trials p= probability of boy Assume p is equal to probability of having a boy First question we are looking for four boys. ie k=4 n = 10 =(10 choose 4) 0.5^4 * (1-.5)^4 = 0.8203 Question 2) At least 7 girls means 1 boy or 0 boys will be born Case 1) 0 boys born Use binomial (10 choose 0) 0.5^0 * (1-.5)^8 = 0.00390625 Case 2) 1 boy born (10 choose 1) 0.5^1 * (0.5)^7 =0.0390625 Case 1 + Case 2= 0.04296875 Probability of at least 7 girls
Is Ruby Bridges have a baby?
no Ruby red is not having another child she already has four boys
In a family of four children what is the probability of having exactly two daughters assuming sons and daughters are equally likely?
50-50
What is the probability that a couple would have a family of four children two boys and two girls and in that order?
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52 in all cases, the overall probability is 0.0624.
What is the probability of tossing four coins and getting four heads if the first two tosses are heads?
The conditional probability is 1/4.
What is the probability of tossing four coins and getting tails on all four?
Assuming it is a fair coin, the probability is 1/24 = 1/16.
What is probabilty?
probability is a math goodie. like two to four. if you have four marbles in a bag and two are red and two are purple then what is the probability? the answer is fifty to fifty or two two four.
