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What is the probability of choosing a red marble or a green marble out of a bag containing 5 blue marbles 3 red marbles and 1 green marble?
Pr = ways_of_success/total_ways
Pr(Red) = 3/(5+3+1) = 3/9
Pr(Green) = 1/9
As they are independent:
Pr(Red or Green) = Pr(Red) + Pr(Green) = 3/9 + 1/9 = 4/9
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Alternatively, as there are only three colours, selecting either Red or Green is the same as not selecting Blue:
Pr(Red or Green) = Pr(not Blue) = 1 - Pr(Blue)
→ Pr(Red or Green) = 1 - 5/9 = 4/9
What else can I help you with?
What are the odds in favor of choosing a white marble from a bag containing 3 black marbles 4 green marbles and 6 white marbles?
The probability of drawing a white marble is .46
What is the probability of choosing a green marble from A jar containing 4 red 7 green and 5 blue marbles?
There are 16 marbles total and 7 green ones, so the probability is 7/16.
What is the probability of choosing blue marble followed by a green marble from a bag containing 5 blue 5 green and 5 red marbles?
The probability of choosing a blue marble is 5 in 15 or 1 in 3. The probability of then choosing a green marble is 5 in 14. (One is missing) Multiply the two probabilities and you get 5 in 42.(P = 0.1190... about 12%).
What is the probability of not choosing a green marble from a jar containing 5 red 6 green and 4 blue marbles?
This is the same as the probability of choosing either a red of a blue marble. There are 5+4 out of 15 ways of doing this. The probability is therefore 9/15 = 3/5.
What is the probability of choosing a green marble from A jar containing 4 red 6 green and 5 blue marbles?
If one marble is chosen at random, the probability is 6/(4+6+5) = 6/15 = 2/5
What are the odds in favor of choosing a white marble from a bag containing 3 black marbles 4 green marbles and 6 white marbles?
The probability of drawing a white marble is .46
What is the probability of choosing a marble that is not blue in problem 2?
if there is a jar containing 5 red marbles 6green and 4 blue what is the probability off not chossing a blue marble
What is the probabilityof choosing a green marble from a jar containing 5 red 6 green and 4 blue marbles?
The probability of choosing a green marble from this jar would be 6/15. You get this answer by adding up the sum of all the marbles.
What is the probability of choosing a green marble from A jar containing 4 red 7 green and 5 blue marbles?
There are 16 marbles total and 7 green ones, so the probability is 7/16.
What is the probability of choosing a marble that is not blue?
it depends how many blue marbles there are and how many marbles total.
What is the probability of choosing blue marble followed by a green marble from a bag containing 5 blue 5 green and 5 red marbles?
The probability of choosing a blue marble is 5 in 15 or 1 in 3. The probability of then choosing a green marble is 5 in 14. (One is missing) Multiply the two probabilities and you get 5 in 42.(P = 0.1190... about 12%).
What is the probability of not choosing a green marble from a jar containing 5 red 6 green and 4 blue marbles?
This is the same as the probability of choosing either a red of a blue marble. There are 5+4 out of 15 ways of doing this. The probability is therefore 9/15 = 3/5.
What is the probability of choosing a red marble from a jar containing. 5 red6green and 4 blue marbles?
5 out of 15 or 1/3 1:3
What is the experimental probability of choosing a green marble if there are 7 red 9 yellow 14 green and 10 purple?
To find the experimental probability of choosing a green marble, first calculate the total number of marbles: 7 red + 9 yellow + 14 green + 10 purple = 40 marbles. The probability of choosing a green marble is the number of green marbles divided by the total number of marbles, which is 14 green / 40 total = 0.35. Thus, the experimental probability of choosing a green marble is 0.35, or 35%.
What is the probability of choosing a green marble from A jar containing 4 red 6 green and 5 blue marbles?
If one marble is chosen at random, the probability is 6/(4+6+5) = 6/15 = 2/5
What is the probability of choosing a green marble from a jar containing 4 red 7green and 5 blue marbles?
7/(4+7+5) = 7/16 = 43.75%
A marble is selected from a random jar containing 3 red marbles 4 yellow marbles and 2 marbles what are the odds in favor of selecting a red marble?
The probability of selecting a red marble is 3/9
