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The answer depends on how many cards are drawn. If 40 are drawn without replacement, from a normal deck, the probability is 1. If 3 are drawn the probability is 0!
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Picking 4 cards out of a deck of 52 what is the probability of picking 3 from one suit and 1 from another suit?
To determine the probability of picking 3 cards of one suit and 1 card of another in a standard 52 card deck, consider each card one at a time. The probability of picking a card in any suit is 52 in 52, or 1. Since there are now only 12 cards in the first suit, the probability of picking a card in the same suit is 12 in 51, or 4 in 17, or 0.2353. Since there are now only 11 cards in the first suit, the probability of picking a card in the same suit is 11 in 50, or 0.22. Since there are still 39 cards in the remaining three suits, the probability of picking a card in a suit different than the first is 39 in 49, or 0.7959. The probability of picking 3 cards of one suit and 1 card of another in a standard 52 card deck is, therefore, the product of the probabilities of each card, or (52 in 52) (12 in 51) (11 in 50) (39 in 49), or 267696 in 6497400, or 0.0412, or about 1 in 25.
What is the probability of drawing 1 card from each suit if 4 cards are drawn from a deck?
The easiest way to do this is to first calculate the probability of drawing spade/heart/club/diamond in order. This is 13/52 times 13/51 time 13/50 times 13/49. Note that each time there are 13 possible cards to choose from out of a shrinking deck. This probability comes out at 0.004396. The reason it's so small is that we haven't accounted for all the different ways you can draw the cards. You might draw the spades first, or the hearts first. There are 4x3x2x1 different orders the cards can come in. Multiply the probability by this and you get 0.1055 So the probability of having 1 card from each suit is 0.1055
What is probability of each suit in a deck of cards?
The probability of each suit in a standard deck of cards is 13 in 52, or 1 in 4, or 0.25.
Find the probability you get a spade or a five on the first draw rounded to one decimal place?
In a standard deck of 52 cards. Probability of drawing a spade: 4 suits, only 1 is spade. Each suit contains A-10 (10 cards) + K + Q + J (3 cards) 13 cards in each suit. There are 13 cards in the spades suit. You have a 13/52 chance of drawing a spade on your first draw. Probability of drawing a 5: there are only 4 5's in the deck. 3/52 chance of drawing a 5. (one 5card per suit that is not spades) 13/52 + 3/52 = 16/52 = .3076 or 30.8% chance of drawing a 5 or a spade on your first pull.
If 2 cards are selected from a standard deck of 52 cards without replacement find the probability that both are the same suit?
If 2 cards are selected from a standard deck of 52 cards without replacement, in order to find the probability that both are the same suit, start with the first card...The probability that the first card is any suit is 52 in 52, or 1.Now, consider the second card. There are 12 cards remaining in the same suit, and 39 cards remaining in the other three suits...The probability that the second card is the same suit as the first card is 12 in 51, or 4 in 17, or 0.235.The probability of both events occurring is the product of those two probabilities. That is still 4 in 17, or 0.235.
How many ways can a hand of five cards consisting of four cards from one suit and one card from another suit be drawn from a standard deck of cards I think combination?
The probability of five cards being four cards from one suit and one card from another suit is the same as the probability of drawing four cards from one suit multiplied by the probability of drawing one card from another suit, multiplied by 5 (for each of the possible positions this other card can be drawn in). The probability of drawing four cards from one suit is 12/51 x 11/50 x 10/49. The probability of drawing a fifth card from another suit is 39/48. All these numbers multiplied together (and multiplied by 5) come to 0.0429. So the probability of drawing a hand of five cards with four cards from one suit and one card from another is 5.29%
What is the probability of drawing a face card given that the card is red?
It is 3/13, and the colour of the suit is irrelevant.
What is the probability of two cards out of a deck of 52 being the same suit if the sampling is done with replacement?
There are four suits, each with an equal number of cards. It doesn't really matter what the first card is, we're just drawing it to get the name of the suit we're looking for on the second draw. So, since there are 4 suits and the probability of each of them is equal, then the overall probability is 1/4 that they're the same suit (and 1/52 that they're the same CARD, since you put it back after the first draw).
What is the probability of drawing a red card out of a deck of 52 cards given a standard deck of 52 cardsqith four suits(2 red and 2 black) with 13 cardsvin each suit?
It is 1/2.
Picking 4 cards out of a deck of 52 what is the probability of picking 3 from one suit and 1 from another suit?
To determine the probability of picking 3 cards of one suit and 1 card of another in a standard 52 card deck, consider each card one at a time. The probability of picking a card in any suit is 52 in 52, or 1. Since there are now only 12 cards in the first suit, the probability of picking a card in the same suit is 12 in 51, or 4 in 17, or 0.2353. Since there are now only 11 cards in the first suit, the probability of picking a card in the same suit is 11 in 50, or 0.22. Since there are still 39 cards in the remaining three suits, the probability of picking a card in a suit different than the first is 39 in 49, or 0.7959. The probability of picking 3 cards of one suit and 1 card of another in a standard 52 card deck is, therefore, the product of the probabilities of each card, or (52 in 52) (12 in 51) (11 in 50) (39 in 49), or 267696 in 6497400, or 0.0412, or about 1 in 25.
What is the probability of drawing 1 card from each suit if 4 cards are drawn from a deck?
The easiest way to do this is to first calculate the probability of drawing spade/heart/club/diamond in order. This is 13/52 times 13/51 time 13/50 times 13/49. Note that each time there are 13 possible cards to choose from out of a shrinking deck. This probability comes out at 0.004396. The reason it's so small is that we haven't accounted for all the different ways you can draw the cards. You might draw the spades first, or the hearts first. There are 4x3x2x1 different orders the cards can come in. Multiply the probability by this and you get 0.1055 So the probability of having 1 card from each suit is 0.1055
When a single card is drawn from an ordinary 52 card deck find the probability of drawing a non-face card or a 7?
Since 7 is already a non-face-card, we know that there is 4 of each suit, and 3 royalty. 4(3) = 12, 52 - 12 = 40. 40/52 = 10/13.
What is the probability when you take a card from a pack it will be a diamond?
There are 4 suits in a deck of cards; each suit has a probability of being selected of 1/4. So, probability of a diamond is 1/4 or 0.25.
What is probability of each suit in a deck of cards?
The probability of each suit in a standard deck of cards is 13 in 52, or 1 in 4, or 0.25.
Find the probability you get a spade or a five on the first draw rounded to one decimal place?
In a standard deck of 52 cards. Probability of drawing a spade: 4 suits, only 1 is spade. Each suit contains A-10 (10 cards) + K + Q + J (3 cards) 13 cards in each suit. There are 13 cards in the spades suit. You have a 13/52 chance of drawing a spade on your first draw. Probability of drawing a 5: there are only 4 5's in the deck. 3/52 chance of drawing a 5. (one 5card per suit that is not spades) 13/52 + 3/52 = 16/52 = .3076 or 30.8% chance of drawing a 5 or a spade on your first pull.
When a card is selected from a deck what is the probability of getting a heart?
There are an equal number of cards for each suit (13 for each), and 52 cards in a deck. Therefore, your odds of selecting one card of any specific suit will always be 13 to 52, or 1 in 4 (a 25% chance).
Probability of drawing above a nine in a deck of 52 playing cards?
If the Ace is considered a high card, then there is approx a 38% probability of drawing above a nine in a standard shuffled deck of 52 playing cards, assuming no cards have already been drawn.Reason:There are five cards above the nine in each suit (10, J, Q, K, A). So there is a five out of thirteen chance (or 20 out of 52); or 38.46%.
