Probability (P) of A or B is: P(A) + P(B) - P(A and B). Apply to the question is: P(Q) + P(Club) - P (Q&Club) = 4/52 + 13/52 - 1/52 = 16/52 = 4/13 or .3077 or 30.77%.
Probability of drawing a heart: 1/4 Probability of drawing a club: 1/4 Probability of drawing a heart or a club: 1/4 + 1/4 = 2/4 = 1/2
The answer depends on how many cards are drawn.
There are 13 clubs in a deck of 52 cards. The probability of drawing 1 club from a deck of 52 is 13/52 or 1/4.
There are 13 clubs in a standard deck of 52 cards. The probability, then, of drawing club is 13 in 52, or 1 in 4, or 0.25.
erm..one in 52?? 1 in 52
Probability of drawing a heart: 1/4 Probability of drawing a club: 1/4 Probability of drawing a heart or a club: 1/4 + 1/4 = 2/4 = 1/2
There is a 13 in 52, or 1 in 4, or 0.25 probability of drawing a club from a standard deck of 52 cards.
The answer depends on how many cards are drawn.
There are 13 clubs in a deck of 52 cards. The probability of drawing 1 club from a deck of 52 is 13/52 or 1/4.
P(club) + P(QS) 1/4 + 1/52 = .25 + .0192 = .269
1 out of 52
There are 13 clubs in a standard deck of 52 cards. The probability, then, of drawing club is 13 in 52, or 1 in 4, or 0.25.
The probability is 22/52 = 11/26.
It is 10/52 = 5/26.
erm..one in 52?? 1 in 52
In a standard deck of 52 cards - the probability of drawing any single card of two suits is 1:2 or 50%.
A standard deck of cards has 52 cards, with 13 hearts and 13 clubs. To find the probability of drawing either a heart or a club, you add the probabilities of each event: ( P(\text{heart}) + P(\text{club}) = \frac{13}{52} + \frac{13}{52} = \frac{26}{52} ). Therefore, the probability of drawing a heart or a club is ( \frac{1}{2} ) or 50%.