6 in 54, or 1 in 9, or about 0.111.
you have a 1/13 chance of getting an ace in a pack of cards
Assuming there are no Joker cards the chance is one in twenty six. There are fifty two cards in a pack and only two of them are black kings.
Assuming there are no Joker cards the chance is one in twenty six. There are fifty two cards in a pack and only two of them are black kings.
If the pick is completely random, the deck is a standard deck and there are no jokers or any other cards other than the standard 52, the probability is 1/4
there are 2 jocker but in card it has 3jocker
you have a 1/13 chance of getting an ace in a pack of cards
25%
Assuming there are no Joker cards the chance is one in twenty six. There are fifty two cards in a pack and only two of them are black kings.
Assuming there are no Joker cards the chance is one in twenty six. There are fifty two cards in a pack and only two of them are black kings.
It is 1: a certainty. A complete pack of cards must have a seven.
A 1/13 Chance (Probability).
10/13
There are 3 face cards in a suit of 13 cards, so the probability is = 3/13.
2.
13/52 = 1/4
It is 1/4.
'The Fool' in the Trumps in the French Tarot Deck, the wild card in a pack of playing cards I am English and we use the word Joker, for the joker in a pack of cards. Can you explain further what you mean?