Well, isn't that a happy little question! In a pack of 54 cards with 2 jokers, you have 4 aces and 2 jokers. So, you have a total of 6 cards that are either aces or jokers. To find the probability, you simply divide the number of favorable outcomes (6) by the total number of outcomes (54). So, the probability of drawing an ace or a joker is 6/54, which simplifies to 1/9. Happy painting!
you have a 1/13 chance of getting an ace in a pack of cards
Assuming there are no Joker cards the chance is one in twenty six. There are fifty two cards in a pack and only two of them are black kings.
Assuming there are no Joker cards the chance is one in twenty six. There are fifty two cards in a pack and only two of them are black kings.
If the pick is completely random, the deck is a standard deck and there are no jokers or any other cards other than the standard 52, the probability is 1/4
there are 2 jocker but in card it has 3jocker
you have a 1/13 chance of getting an ace in a pack of cards
25%
Assuming there are no Joker cards the chance is one in twenty six. There are fifty two cards in a pack and only two of them are black kings.
Assuming there are no Joker cards the chance is one in twenty six. There are fifty two cards in a pack and only two of them are black kings.
It is 1: a certainty. A complete pack of cards must have a seven.
A 1/13 Chance (Probability).
10/13
There are 3 face cards in a suit of 13 cards, so the probability is = 3/13.
2.
It is 1/4.
13/52 = 1/4
The probability is 0 if you pick the the card from one end of a mint pack (2 of clubs) and 1 if you pick it from the other end (A spades). Also, if you pick 49 cards without replacement, the probability is 1. So, the answer depends on how many cards are drawn, and whether or not they are drawn from a well shuffled pack. The probability of getting an ace when one card is randomly picked from a pack is 4/52 = 1/13.