One way to do this is to look at the probability of rolling a 7. Let's call that P(7) and the probability we seek is 1-P(7) Now we look at how many ways there are to get 7 with two dice 1+6 or 6+1 4+3 or 4+3 5+2 or 2+5 The sample space is 36 outcomes and there are 6 way to get 7 so 6/36=1/6 So the probability that the sum is 7 is 1/6 and 1-1/6=5/6 The answer is 5/6 ( my guess it that is higher than one might guess? You could also do the problem directly. Let's look at how to NOT get a sum of 7 1+2 or 2+1 1+3 or 3+1 1+4 or 4+1 1+5 or 5+1 2+3 or 3+2 2+4 or 4+2 2+6 or 6+2 3+5 or 5+3 3+6 or 6+3 4+5 or 5+4 4+6 or 6+4 5+6 or 6+5 6+6 5+5 4+4 3+3 2+2 1+1 There are 30 of these so 30/36 is 5/6
Since there are two permutations of two dice that sum to 11, (5-6) and (6-5), and since there are 36 permutations of rolling two dice, the probability of not rolling a sum of 11 is 34 in 36, or 17 in 18, or about 0.9444.
The probability is 1.
The probability of rolling a sum of 8 and doubles when rolling two dice is 1 in 36, or about 0.02778. Simply note that there are 36 permutations of two dice, of which exactly one of them (a 4 and a 4) matches the conditions specified.
There is 4 ways to roll a 9 with 2 dice, and 36 possible outcomes. So, the probability of rolling a sum of 9 with two dice is 4/36 or 1/9.
Singular: die Plural: dice Nonsense: dices! The probability is 2/36 = 1/18
Zero is the probability of rolling a sum of 15 on two fair dice; the maximum value is 12.
The probability of not rolling a sum of six with two fair dice is 1 minus the probability of rolling a sum of six. There are 36 permutations of rolling two dice. Of these, five sum to six, 1+5, 2+4, 3+3, 4+2, and 5+1. The probability, then of rolling a sum of six is 5 in 36. The probability, then of not rolling a sum of six is 31 in 36, or about 0.8611.
5 in 36
Since there are two permutations of two dice that sum to 11, (5-6) and (6-5), and since there are 36 permutations of rolling two dice, the probability of not rolling a sum of 11 is 34 in 36, or 17 in 18, or about 0.9444.
The probability of rolling a sum of 12 in a single roll of two dice is 1 in 36, or about 0.0278.
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
The probability is 1, if the dice are rolled often enough.
The probability of rolling a sum of 8 and doubles when rolling two dice is 1 in 36, or about 0.02778. Simply note that there are 36 permutations of two dice, of which exactly one of them (a 4 and a 4) matches the conditions specified.
The probability is 1.
The probability is 29/36.
There are 36 permutations of two dice. Only one of them has a sum of two. Then probability, then, of rolling a sum of more than two is 35 in 36, or about 0.9722.
35/36