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What is the probability of rolling two dice and the sum is greater than 5?
The probability is 26/36 or 13/18
What is the probability to obtain in sum the numbers 7 and 13 by throwing 3 dice?
Probability(Total = 7) = 15/216 = 0.069 Probability(Total = 13) = 21/216 = 0.097
If you roll two standard dice what is the probability that the sum of their spot values will be a prime number?
13/36
What is the probability of rolling a 7 with two dice?
The probability or rolling a 7 with one roll of a pair (2) dice is 0.166666.... We get this number by dividing 6 by 36 (or 1 by 6). Let's review what a probability is and then find out how we get the 6 and the 36.We know that probabilities range from zero (0) to one (1), inclusive. A probability of 0 means that a given result cannot happen. Like rolling a 13 with one toss of a pair of dice. The largest number that can appear is 12, so rolling a 13 cannot be done. The probability of that happening is 0.A probability of 1 means it must happen. Like rolling a number between 2 and 12, inclusive, with one roll of the dice. Rolling a 2, 3, 4, 5, 6 7, 8, 9, 10, 11, or 12, is something that must happen, so the probability of that is 1. All probabilities that something will happen will fall on or between 0 and 1. All of them. Some folks often interchange the term probability with "the odds" of something happening, and this might be the cause of some confusion. Now that we've reviewed probability, let's look at odds and see where the numbers come from.There are 6 ways to make a 7 with two dice. They are 1-6, 2-5, 3-4, 4-3, 5-2, and 6-1. And there are 36 (6 x 6) possible outcomes with a single roll of two dice. The odds of a 7 coming up are 6 in 36, or 1 in 6. As this is true, the probability of the 7 appearing will be the number of times the combination is possible (6) divided by the total possible combinations (36), which leads us to 6 divided by 36 or 1 divided by 6, or 0.166666....Use the link to the Related question to see about the odds of rolling that 7 with two dice.
What is the probability of rolling at least one six with one roll of a pair of dice?
To find the probability of rolling at least one six with one roll of a pair of dice, we need to know two things. First we need to know how many different possible outcomes there are when we roll the dice one time. We know that there are 36 different possible outcomes. They are 1-1, 1-2, 1-3,..., 6-4, 6-5 and 6-6.We also need to know how many different times at least one six can appear. These will include, 1-6, 2-6, 3-6, 4-6, 5-6, 6-6, 6-1, 6-2, 6-3, 6-4, and 6-5, for a total of 11 possible outcomes with at least one six. (Note that the 6-6 possible outcome is included in the list because it fits the requirement of "at least one six" with a given single pass of the dice.The odds of rolling at least one six in one pass with a pair of dice are 11 in 36. To find the probability of this, we need to divide the 11 by the 36, and this gives us a probability of 11/36 or 0.3055555....Remember that probability is a ratio, and it's the ratio of the number of possible times a given outcome can appear to the total number of possible outcomes that could appear. This ratio will range from zero to one, inclusive. A probability of zero means that a given outcome cannot occur. Like rolling a 13 with one pass of a regular pair of dice. That can't happen, so the probability of it happening is zero.We also understand that if the probability of something happening is one, then that outcome must happen. Like the probability of rolling an odd or an even number. We know that an odd or an even number must appear, so the probability of that happening is one.
