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What_is_the_probability_of_spinning_a_free_on_one_spin_and_an_s_on_your_second_if_you_have_a_spinner_with_1_space_labeled_free_and_the_remaining_11_mississippi_with_one_letter_in_each.

So, you would multiply 1/12 times 4/12 to get 4/144 or 1/36

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Q: What is the probability of spinning a free on one spin and an s on your second if you have a spinner with 1 space labeled free and the remaining 11 Mississippi with one letter in each.?
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