There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.
However, if you assume that they are independent events then, given that the probability of a boy is approx 0.5169, the probability of the event described is 0.5169*1*1*0.4831 = 0.2497
50%
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.If you believe that the children's genders are not independent then you would need to get empirical evidence from all families with four or more children in which the first three children were girls. If there are g families in which the fourth is a girl and b where the fourth is a boy then the required probability is b/(g+b).However, if you assume that the children's genders are independent events then, given that the probability of a boy is approx 0.52, the probability of the fourth child is a boy is 0.52
0.25 binomial distribution, where p=0.5, q=0.5, x=3, n=4 4!/(3!*1!)*0.530.51 = 0.25 Also can be solved by identifying each event possible and related probability. There are 4 ways this can occur (first child is a girl, second child is a girl, third child is a girl and fourth child is a girl) and there is a 0.54 chance of each of these events occurring. Prob= 4 *0.0625 = 0.25
50% then 25%
zero...
The answer to this is 1 minus the probability that they will have 3 or fewer children. This would happen only if they had a boy as the first, second or third child. The probability they have a boy as first child is 0.5 The probability they have a boy as second is 0.25 The probability they have a boy as third is 0.125 Thus the total probability is 0.875 And so the probability they will have more than three children is 1-0.875 or 0.125
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. A family of 4 is a family of two parents and two children. The probability that both children are girls is 0.2334
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.However, if you assume that children's genders are independent events then, given that the probability of a girl is approx 0.48.
50%
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.If you believe that the children's genders are not independent then you would need to get empirical evidence from all families with four or more children in which the first three children were girls. If there are g families in which the fourth is a girl and b where the fourth is a boy then the required probability is b/(g+b).However, if you assume that the children's genders are independent events then, given that the probability of a boy is approx 0.52, the probability of the fourth child is a boy is 0.52
Assuming both children are on the same side of the family, your child's first cousin is a second cousin to your first cousin's child. Your child is also a second cousin to your first cousin's child. Your child can have first cousins who are not related to your first cousin and thus not related to your first cousin's child.
The family and their home is a child's first method of socialization. Therefore, the types of buying decisions that members of a family make influence the decisions that the child later makes.
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of the other two being boys is 0.2672.
0.25 binomial distribution, where p=0.5, q=0.5, x=3, n=4 4!/(3!*1!)*0.530.51 = 0.25 Also can be solved by identifying each event possible and related probability. There are 4 ways this can occur (first child is a girl, second child is a girl, third child is a girl and fourth child is a girl) and there is a 0.54 chance of each of these events occurring. Prob= 4 *0.0625 = 0.25
50% then 25%
50%
Your first cousin and your grandchildren (your child's children) are first cousins once removed.