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I assume you mean what's the chance of at least two heads showing when three fair coins are tossed.

There are 8 possible outcomes as each coin can either be head or tails.

For 3 heads, all 3 coins must show a head → 1 success

For 2 heads, one coin will be a Tail; each coin could be a tail in turn → 3 successes

→ Pr = (1+3)/8 = 4/8 = 1/2

If you are wanting the probability that the first TWO specific coins are heads and the last, third, coin is either, then:

Pr(head) = 1/2

→ Pr(1st 2 heads, 3rd anything) = 1/2 × 1/2 × 1 = 1/4

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