It is 1, since it falls on a Wednesday.
2/5
2/7, as there 7 days in a week.
The probability of at least 1 match is equivalent to 1 minus the probability of there being no matches. The first person's birthday can fall on any day without a match, so the probability of no matches in a group of 1 is 365/365 = 1. The second person's birthday must also fall on a free day, the probability of which is 364/365 The probability of the third person also falling on a free day is 363/365, which we must multiply by the probability of the second person's birthday being free as this must also happen. So for a group of 3 the probability of no clashes is (363*364)/(365*365). Continuing this way, the probability of no matches in a group of 41 is (365*364*363*...326*325)/36541 This can also be written 365!/(324!*36541) Which comes to 0.09685... Therefore the probability of at least one match is 1 - 0.09685 = 0.9032 So the probability of at least one match is roughly 90%
The probability that the birthdays of five persons chosen at random will fall in twelve different calender months is zero. You would need at least twelve persons to have a non zero probability.
If you fall from any given height, whether or not you get hurt will depend on a large number of factors: what you fall on, how you fall, whether or not there was something that broke your fall on the way down and so forth.
A probability density function (pdf) for a continuous random variable (RV), is a function that describes the probability that the RV random variable will fall within a range of values. The probability of the RV falling between two values is the integral of the relevant PDF. The normal or Gaussian distribution is one of the most common distributions in probability theory. Whatever the underlying distribution of a RV, the average of a set of independent observations for that RV will by approximately Gaussian.
This year (2016), it is 0.2842, approx.
74 %
one in seven7 days a week
1/7
aster
Fall.
2/7, as there 7 days in a week.
The probability of at least 1 match is equivalent to 1 minus the probability of there being no matches. The first person's birthday can fall on any day without a match, so the probability of no matches in a group of 1 is 365/365 = 1. The second person's birthday must also fall on a free day, the probability of which is 364/365 The probability of the third person also falling on a free day is 363/365, which we must multiply by the probability of the second person's birthday being free as this must also happen. So for a group of 3 the probability of no clashes is (363*364)/(365*365). Continuing this way, the probability of no matches in a group of 41 is (365*364*363*...326*325)/36541 This can also be written 365!/(324!*36541) Which comes to 0.09685... Therefore the probability of at least one match is 1 - 0.09685 = 0.9032 So the probability of at least one match is roughly 90%
the day
When they say night begins to fall actually means darkness appears therefore night fall.
My birthday will fall on 22 February 2010.
The way to look at this probability is that it is equally likely for your birthday to fall on any given day of the week. There is a 1/7 chance it will land on Saturday. There is a 1/7 chance it will land on Sunday, and so on for all the other days. Taking this into account, it is clear that there is a 1/7 chance of your birthday falling on whatever day you were born.