sample space = 1, 2, 3, 4
The sample space of a standard six sided die rolled twice, or two dice rolled once (they are the same) is [11, 12, 13, 14, 15, 16, 21, 22, 23, 24, 25, 26, 31, 32, 33, 34, 35, 36, 41, 42, 43, 44, 45, 46, 51, 52, 53, 54, 55, 56, 61, 62, 63, 64, 65, 66].
The sample space is:11, 12, 13, 14, 15, 16, 21, 22, 23, 24, 25, 26, 31, 32, 33. 34, 35, 36, 41, 42, 43, 44, 45, 46, 51, 52, 53, 54, 55, 56, 61, 62, 63, 64, 65, 66. P(Alana wins) = 1/36 if the dice are fair.
The variance of this data set is 22.611
Distribution would be centered at .14*128=17.92The standard deviation of the distribution would be root(n(p(p-1)))=root(128*.14*.86)=3.92571013Normal, unimodal
False. A sample which contains two elements whose index value is smaller than the sampling increment will never be chosen. For example, if the increment is 5, then you could choose 1, 6, 11, ... or 2, 7, 12, ... or 3, 8, 13, ... or 4, 9, 14, ... or 5, 10, 15, ... but the sample comprising 1, 3, 4, ... cannot be chosen.
Partial answer: Assuming that the dice show the numbers 1, 2, 3, ... 14 on each die, and that the question refers to throwing both dice and getting the sum. The smallest sum is 2 and the greatest sum is 28. So the sample space is 2,3,4,...,28.
Bill Nye the Science Guy - 1993 Spinning Things 3-14 was released on: USA: 15 September 1995
9 half lives have elapsed to yield a sample with 125 atoms of C-14 and 375 atoms of N-14.
The variance is: 1.6709957376e+13
Lost in Space - 1965 Castles in Space 3-14 is rated/received certificates of: Australia:G
Lost in Space - 1965 Castles in Space 3-14 was released on: USA: 20 December 1967
Space Angel - 1962 Visitors from Outer Space 1-14 was released on: USA: 1962
No and yes. It depends on the way you define activity. Carbon-14 undergoes radioactive beta decay. The activity of Carbon-14 is given in terms of disintegrations per minute per gram of carbon. So, if you have a 100 gram sample and a 1 gram sample, there will be 100 times more disintegrations per minute with the larger sample. But typically, we are more interested in the time it takes a certain percentage to decay. Time values like half life will be the same for large and small samples.
No, there are no detectable levels of carbon-14 left in any sample older than roughly 40,000 years. Without carbon-14 in the sample, no date can be determined.
it takes 14 mins to get information in space
14 on the space shuttle
t is equal to = (1/2)ln(A/A0))