standard error for proportion is calculated as:
SE = sqrt [(p)(1-p) / n ]
so let us say that "p" is going to represent the decimal proportion of respondents who said YES.... so...
p = 20/25 = 4/5 = 0.8
And... we then are going to say that the complement of "p" which is "1-p" is going to represent the decimal proportion of respondents who said NO ... so... 1-p = 1 - 0.8 = 0.2
Lastly, the "n" in the formula for standard error is equal to 25 because "n" represents the sample size....
So now all you have to do is plug the values you found for "p" and for "1-p"... (remember "p = 0.8" and "1-p = 0.2")... and "n=25"....
Standard Error (SE) = sqrt [(p)(1-p) / n ]
............................ = sqrt [(0.8)(1-0.8) / 25 ]
............................ = sqrt [(0.8)(0.2) / 25 ]
............................ = sqrt [0.16 / 25]
............................ = sqrt (0.0064)
............................ = +/- 0.08
The mean of a proportion, p, is X/n; where X is the number of instances & n is the sample size; and its standard deviation is sqrt[p(1-p)]
It is 6.1, approx.
it is the test one tail
A small sample size and a large sample variance.
3 percent
To calculate the standard error for a proportion, you can use the formula: [ SE = \sqrt{\frac{p(1 - p)}{n}} ] where (p) is the sample proportion and (n) is the sample size. If the proportion is not given in your question, you'll need to specify a value for (p) to compute the standard error. For a sample size of 25, substitute that value into the formula along with the specific proportion to find the standard error.
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The proportion is approx 95%.
The mean of a proportion, p, is X/n; where X is the number of instances & n is the sample size; and its standard deviation is sqrt[p(1-p)]
The sample distribution of the sample proportion refers to the probability distribution of the proportion of successes in a sample drawn from a population. It is typically approximated by a normal distribution when certain conditions are met, specifically when the sample size is large enough (usually np and n(1-p) both greater than 5). The mean of this distribution is equal to the population proportion (p), and the standard deviation is calculated using the formula √[p(1-p)/n]. This distribution is useful for making inferences about the population proportion based on sample data.
0.0016
The sampling distribution of (\hat{p}) (the sample proportion) describes the distribution of sample proportions obtained from repeated random samples of a given size from a population. It is approximately normal when the sample size is large enough, typically when both (np) and (n(1-p)) are greater than 5, where (p) is the population proportion and (n) is the sample size. The mean of this distribution is equal to the population proportion (p), and the standard deviation (standard error) is given by (\sqrt{\frac{p(1-p)}{n}}).
It is 6.1, approx.
it is the test one tail
A half.
A small sample size and a large sample variance.
3 percent