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What is the z score if 30.5 percent of the curve lies to the left of the z?
It is -0.51
Find the z-score for which 92 percent of the distribution's area lies between -z and z?
z = 1.75
What is the z score if 30 percent of the curve lies to the left of the z?
The z-score is 0.84. In the related link, look in the body of the table for .3 area (.2995 closest) and it yields the .84 z-score.
The standard z-score such that 80 percent of the distribution is below to the left of this value is?
z = 0.8416
What is the probability that a data value in a normal distribution is between a z-score of -1.98 and a z-score of 1.11 Round your answer to the nearest tenth of a percent?
It is 84.3%
What is the z score for 80 percent percent confidence?
80 percent percent = 0.008. The two tailed z-score for 0.008 is 2.652
What is the z score if 30.5 percent of the curve lies to the left of the z?
It is -0.51
What is the z score if 65 percent of the curve lies to the right of z?
-0.38532
What z score corresponds to 40 percent between the mean and the z?
z = 1.28, approx.
Find the z-score for which 92 percent of the distribution's area lies between -z and z?
z = 1.75
What is the z score if 30 percent of the curve lies to the left of the z?
The z-score is 0.84. In the related link, look in the body of the table for .3 area (.2995 closest) and it yields the .84 z-score.
What are the z-score boundaries for the middle of 50 percent of the distribution?
50 * * * * * z = -0.67449 to z = +0.67449
What Z score corresponds to 17 percent of the data between the mean and the Z?
z value=0.44
What z-score separates the top 10 percent from the rest of the scores?
z = 1.281551
In a standard normal distribution about percent of the scores fall above a z score of 300?
A Z score of 300 is an extremely large number as the z scores very rarely fall above 4 or below -4. About 0 percent of the scores fall above a z score of 300.
What Z score correspnods to 19 percent of the date between mean and the Z?
A z score of .5 corresponds to 19% of the data between the mean and z. P( 0 < z < .5) = .19
The standard z-score such that 80 percent of the distribution is below to the left of this value is?
z = 0.8416
