One of the main reasons for doing so is to check that the assumptions of the errors being independent and identically distributed is true. If that is not the case then the simple linear regression is not an appropriate model.
The given statement is true. Reason: High multicollinearity can make it difficult to determine the individual significance of predictors in a model.
True , it would have been false only if it was mentioned no relationship . But as it mentions linear it is true.
That is not true. It is possible for a data set to have a coefficient of determination to be 0.5 and none of the points to lies on the regression line.
To take a simple case, let's suppose you have a set of pairs (x1, y1), (x2, y2), ... (xn, yn). You have obtained these by choosing the x values and then observing the corresponding y values experimentally. This set of pairs would be called a sample.For whatever reason, you assume that the y's and related to the x's by some function f(.), whose parameters are, say, a1, a2, ... . In far the most frequent case, the y's will be assumed to be a simple linear function of the x's: y = f(x) = a + bx.Since you have observed the y's experimentally they will almost always be subject to some error. Therefore, you apply some statistical method for obtaining an estimate of f(.) using the sample of pairs that you have.This estimate can be called the sample regression function. (The theoretical or 'true' function f(.) would simply be called the regression function, because it does not depend on the sample.)
It could be any value
One of the main reasons for doing so is to check that the assumptions of the errors being independent and identically distributed is true. If that is not the case then the simple linear regression is not an appropriate model.
true
Yes.
true, liner regression is useful for modeling the position of an object in free fall
Your question is a bit hard to understand, but I'll do my best. Sometimes taking the log of your independent variable will improve a linear fit. If you have two sets of data, X and Y, and they don't seem to fit a linear relationship, you may take the log of X, and the log of X may fit a linear relationship. Example: Suppose your data correctly fits the model y = a Xm. So plotting Y and X*, where X* is the log of X, and performing a linear regression, you obtain a slope and intercept. Your intercept is log(a). If you are using log base 10, then a (in the model) = 10intercept value and m is the slope of the semi-log line.
In graph form, the linear equation lies below the true line or curve.
Regression are classified as - Full / Complete Regression -- Entire application is regressed - Regional regression -- Tests performed around defect fixes or code changes
The given statement is true. Reason: High multicollinearity can make it difficult to determine the individual significance of predictors in a model.
True.
It has no linear dimensions.
Yes, in a linear programming model on a spreadsheet, the measure of performance is typically located in the target cell, which is often the cell that you are trying to either maximize or minimize by changing the decision variables. The goal is to optimize the measure of performance by finding the best values for the decision variables based on the constraints of the model.