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3 and 45, for a start.

And then, for simplicity, you can add any pair of numbers between these two which are the same distance from 24.

For example, any pair 24 - a and 24 + a where a ≤ 21 will do.

It is, also possible to add sets of three or more, but they will take a little bit more effort.

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13y ago

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How many 6 combination numbers are there in 42 numbers?

42C6 = 5245786


What is the mean of 31 42 34 21 33 31?

the mean of 31 42 34 21 33 31 is 192


What is the mean median mode and range of 43 37 38 46 35 42?

Mean: 40.17Median: 40Mode:noneRange: 1135, 37, 38, 42, 43, 46Mean is the average:(35 + 37 + 38 + 42 + 53 + 56)/6 = 241/6 = 40.17Median is the middle value in the list = 3rd & 4th values(38 +42)/2 = 80/2 =40Mode is thenumber that is repeated more often =noneRange is the largest value and the smallest value = 46 - 35 = 11


What two numbers when added equal 48?

Working only with positive numbers*, any of the following would do. 1 + 47 2 + 46 3 + 45 4 + 44 5 + 43 6 + 42 7 + 41 8 + 40 9 + 39 10 + 38 11 + 37 12 + 36 13 + 35 14 + 34 15 + 33 16 + 32 17 + 31 18 + 30 19 + 29 20 + 28 21 + 27 22 + 26 23 + 25 24 + 24 * if negative numbers are allowed then there is an infinite range 49 - 1 50 - 2 51 - 3 ... and so on in an endless sequence adding 1 to each value.


Answers for For how many different counting numbers between 10 and 200 is the sum of the digits equal to 6 if zero is not a digit of any numbers?

Between 10 and 100 say we have the number 10a+b where 0<a,b<10. Now, we want numbers such that a+b = 6. Clearly there are 5 solutions: (a,b) = (1,5),(2,4),(3,3),(4,2),(5,1) corresponding to the numbers 15, 24, 33, 42 and 51. Now between 100 and 200 we have numbers of the form 100+10a+b with 1+a+b=6 or equivalently a+b=5. Here we have 4 solutions: (a,b) = (1,4),(2,3),(3,2),(4,1) corresponding to the numbers 114, 123, 132 and 141. So all in all we have 9 solutions: 15, 24, 33, 42, 51, 114, 123, 132 and 141

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