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Juvenal Dare

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3y ago
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12y ago

Proportion of scores between -2 and 1 in a normal distribution is φ(1)-φ(-2) = .8413-.0228 = .8185.

.8185 = 81.85 %

Here φ(t) = P(x ≤ t)

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Q: What percentage of scores in a normal distribution would fall between z-scores of 1 and -2?
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