It is an experimental trial.
The probability of tails on the next toss is 1/2=.5 since this event is INDEPENDENT of the prior events.
The probability of tossing a coin twice and getting tails both times is 1 in 4, or 25%. If you have already tossed a coin and had it land on tails, the probability that it will land on tails again the next time you toss it is 50%.
1/16 - if it is a fair coin.
Each time you flip a fair coin it has the same equal chance of landing on heads or tails. That is, even if you get (for example) 19 heads in a row, the next flip still has 50% chance of landing on tails (if the coin is fair).
24 times
It is a simple experimental trial.
Since there is only 2 sides to a coin...tails will come up 50% of the time.
The probability of tails on the next toss is 1/2=.5 since this event is INDEPENDENT of the prior events.
It is either heads or tails.
The probability of tossing a coin twice and getting tails both times is 1 in 4, or 25%. If you have already tossed a coin and had it land on tails, the probability that it will land on tails again the next time you toss it is 50%.
1/16 - if it is a fair coin.
The side heads is slightly heavier giving it a greater likely hood of landing on tails.
The probability of the coin coming up heads each time is 1/8; likewise for 3 tails. The probability of getting 2 heads and 1 tail (in any order) or 2 tails and 1 head, is 3/8. There are lots of other events whose probability can be calculated when a coin is tossed 3 times, but the question doesn't specify what event is to have its probability calculated.
Each time you flip a fair coin it has the same equal chance of landing on heads or tails. That is, even if you get (for example) 19 heads in a row, the next flip still has 50% chance of landing on tails (if the coin is fair).
Every time you flip a coin it has a 50% probability that it will land on either heads or tails. You would expect to get heads about half the time and tails about half the time. What actually happens could be different from what is expected. You could get heads every time, or tails every time. Or you could get tails 75% of the time and heads 25% of the time. however, your results appear to be what you would expect, approximately 50% heads and 50% tails. You got 16 heads and 14 tails. Your percentage of heads is 16/30 x 100= 53.33... %. Your percentage of tails is 14/30 x 100 = 46.66... %.
We need to determine the separate event. Let A = obtaining four tails in five flips of coin Let B = obtaining at least three tails in five flips of coin Apply Binomial Theorem for this problem, and we have: P(A | B) = P(A ∩ B) / P(B) P(A | B) means the probability of "given event B, or if event B occurs, then event A occurs." P(A ∩ B) means the probability in which both event B and event A occur at a same time. P(B) means the probability of event B occurs. Work out each term... P(B) = (5 choose 3)(½)³(½)² + (5 choose 4)(½)4(½) + (5 choose 5)(½)5(½)0 It's obvious that P(A ∩ B) = (5 choose 4)(½)4(½) since A ∩ B represents events A and B occurring at the same time, so there must be four tails occurring in five flips of coin. Hence, you should get: P(A | B) = P(A ∩ B) / P(B) = ((5 choose 4)(½)4(½))/((5 choose 3)(½)³(½)² + (5 choose 4)(½)4(½) + (5 choose 5)(½)5(½)0)
For 4 coin tosses, there are 16 possible outcomes. Tails on 75% of 4 tosses is 3 times tails, and 1 time heads. This occurs in 4 of those 16 possibilities, so the probability is 4/16 = 1/4 (or 25%). But if the question is 'what is the probability that it's tails at least 75% of the time, then you have to add in the 1 where all 4 are tails, then you have 5/16 (or 31.25%).