1 Arrange the numers in ascending orfder, 0, 1, 1, 1, 4, 4. For sets of numbers that are even, it is common to use the average of the middle two numbers, in this case (1+1)/2 1
Oh, what a lovely question! To find the median, we first need to arrange the numbers in numerical order. So, it would be 0, 1, 2, 3, 4, 5. Since there are six numbers, the median would be the middle number when arranged, which in this case is 2.
The median is the middle number of any given set when they are in order, least to greatest. If there is an even number of values, the median is the average of the middle two. Ex. (10, 17, 20, 45, 68) The median is 20.
Ans. 4.5 Explanation: The median for an even set of numbers is (Xn+Xn+1)/2 where n = number of values in dataset divided by 2 and Xn is the nth ranked value when sorted from lowest to highest. Your ordered set is S=(0,1, 2, 3, ,...9) at least I think it is, with 10 values , X1 = 0, X2 =1, ..., so median = (4+5)/2 = 4.5. There are five numbers lower than 4.5 (0,1,2,3,4) and five numbers higher (5,6,7,8,9).
The median of 00000201 is 0 The way to figure is out is: 1. put them into ascending order (lowest to highest) 2. cross off the each end number like this : 0 0 0 0 0 0 1 2 3. keep going : 0 0 0 0 0 0 1 2 4. if there is one number left in the middle, that's the answer, but if there's two, you divide them: so in this case, is: 0 / 0
Say you have the numbers 3 5 6 4 4 4 5 6 0 2 4.Line them up in numerical order.0 2 3 4 4 4 4 5 5 6 6The middle number is the median.So 4.
The median numbers are 1 and 0. This is because there is no middle number.
The median numbers are 1 and 0. This is because there is no middle number.
the median is the middle in a set of numbers so if you had a set of 5 numbers like -2, -1, 0, 1, and 2 the middle number would be zero.
If you have a list of positive and negative numbers then it is possible that the median would be 0.
Oh, what a lovely question! To find the median, we first need to arrange the numbers in numerical order. So, it would be 0, 1, 2, 3, 4, 5. Since there are six numbers, the median would be the middle number when arranged, which in this case is 2.
Assuming the set is 4 4 0 3 2 5, the median would be the center number of the ordered set 0 2 3 4 4 5, which would be between 3 and 4, so the answer is 3.5
You need to put these into order: 0,1,1,1,4,4 The median is the middle number. In this case where we have an even amount of scores, the median is the average of the two middle numbers. Here the two middle numbers are 1, 1. The average of these is 1. This is our median.
This is not possible, as to be the median the number must be part of the set and 0 is not a positive number. If 0 was meant to be included, the set would have to consist of more 0 terms than all other terms combined. That is, if x were any positive integer, 0, x, x or 0, 0, x, x could not have a median of 0, while 0, 0, 0, x, x would for certain.
if you had these numbers; 0 1 2 3 4 5 6 7 8 9 and you crossed off all the numbers to get 4 and 5 the median would either be the number between them; 4.5 or you could say there is no median; nm hope this helps :D
The median is 3.5, the number halfway between the two middle numbers when they are in order.
Median is the middle number; set in ascending order (0, 1, 4, 6, 8). Since there is an odd number of values, it is easy to pick the middle number which is 4.
In ord they would be 2,3,4,5,6,6,9. The mean is all of the numbers added up and divided by how many numbers there are. So it would be 2+3+4+5+6+6+9 divided by 7. So the mean is 5. The median is the number in the middle so the median is 5. If the median is 2 numbers it is the number in between those numbers. The mode is the number that is occurring the most. If there is no mode put a 0 with a slash through it which means no answer. The mode is 6 because it occurs twice and no other number does that or more. The range is the difference (subtraction) between the biggest number and the smallest number. The biggest number is 9 and the smallest number is 2. So the range would be 9-2 which is 7. Mean=5 median=5 mode=6 range= 7