In the experiment of throwing two fair dice the probability of having 11 or 12 as the
sum of the two numbers that turn up is:
P(x=12) = 1/36, and P(x=11) = 2/36
So, P(x<11) = 1 - [P(x=12) + P(x=11)] = 1 - 3/36 = 33/36 = 0.91666...
≈ 91.7%
If two dice (not dices!) are thrown then the probability that you get an even number on one die is 27/36 = 3/4
It is 11/18.
the probability is 2/6 or 1/3
one in six
The probability is 5/16 = 0.3125
If two dice (not dices!) are thrown then the probability that you get an even number on one die is 27/36 = 3/4
It is 11/18.
It is not possible to answer the question with no knowledge of the numbers on the sides.
The first dice can show any number. However the second dice has a 1 in 6 chance of being the same as the first. Hence the probability of getting two numbers the same is 1/6.
1/36
None of the digits can be 10, so the probability is 0.
the probability is 2/6 or 1/3
one in six
The probability is 5/16 = 0.3125
The first dice can show any of the eight numbers. If the dice are to show different numbers the second dice has 7 different numbers out of a possible 8 to chose from. So the probability is 7/8 or 0.875 or 87.5% chance.
You have more chance with two dice rolled together ! The Probability of throwing a six with one dice is 1/6. The probability of throwing one six with two dice is 2/6 or 1/3. You're twice as likely to score a six if you're throwing two dice.
11 ---- 36