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In the experiment of throwing two fair dice the probability of having 11 or 12 as the

sum of the two numbers that turn up is:

P(x=12) = 1/36, and P(x=11) = 2/36

So, P(x<11) = 1 - [P(x=12) + P(x=11)] = 1 - 3/36 = 33/36 = 0.91666...

≈ 91.7%

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Q: When two dice are thrown simultaneously what is the probability that the sum of two numbers that turn up is less than 11?
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